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lubasha [3.4K]
3 years ago
13

Put these in order starting from the smallest. 6² 3⁴ 2⁵ 5³

Mathematics
2 answers:
natima [27]3 years ago
4 0

Answer:

Answer is in this attachment

vovikov84 [41]3 years ago
4 0

Answer:

2^5 < 6^2 < 3^4 < 5^3

Step-by-step explanation:

Solve each one:

6^2 = 6*6=36

3^4 = 3*3 =9*3 =27*3 = 81

2^5 = 2*2 = 4*2= 8*2 = 16*2 = 32

5^3 = 5*5 = 25*5 = 125

32 < 36 < 81 < 125

So:

2^5 < 6^2 < 3^4 < 5^3

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Please please answer (-2)(-4)(-1)(-7)(1) = and explain
gregori [183]

Answer:

56

Step-by-step explanation:

(-2)(-4)(-1)(-7)(1) =

(8)(-1)(-7)(1) =

(-8)(-7)(1) =

(56)(1) = 56

hope this helps

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6 0
3 years ago
Do only 6 and 7 , 7th grade math
Paha777 [63]
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7 0
3 years ago
Help?? I could really use it
Lynna [10]

Answer:

16.5 m

Step-by-step explanation:

The triangle shown in the figure is a right triangle, so we can use the Pythagoreas Theorem.

a² + b² = c²

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4 0
3 years ago
In a survey of 269 college students, it is found that
Degger [83]

Answer: a) 83, b) 28, c) 14, d) 28.

Step-by-step explanation:

Since we have given that

n(B) = 69

n(Br)=90

n(C)=59

n(B∩Br)=28

n(B∩C)=20

n(Br∩C)=24

n(B∩Br∩C)=10

a) How many of the 269 college students do not like any of these three vegetables?

n(B∪Br∪C)=n(B)+n(Br)+n(C)-n(B∩Br)-n(B∩C)-n(Br∩C)+n(B∩Br∩C)

n(B∪Br∪C)=69+90+59-28-20-24+10=156

So, n(B∪Br∪C)'=269-n(B∪Br∪C)=269-156=83

b) How many like broccoli only?

n(only Br)=n(Br) -(n(B∩Br)+n(Br∩C)+n(B∩Br∩C))

n(only Br)=90-(28+24+10)=28

c) How many like broccoli AND cauliflower but not Brussels sprouts?

n(Br∩C-B)=n(Br∩C)-n(B∩Br∩C)

n(Br∩C-B)=24-10=14

d) How many like neither Brussels sprouts nor cauliflower?

n(B'∪C')=n(only Br)= 28

Hence, a) 83, b) 28, c) 14, d) 28.

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3 years ago
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spayn [35]

Answer:

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2 years ago
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