Question

Jamie wants to build a rectangular fence around a new chicken pen he can afford at most 70 ft long of fencing and must fit the pen in a space that is 10 ft by 2"12 ft could the pen measure 9ft by 22ft why or why not

Answer 1

Using the perimeter of a rectangle, it is found that:

With these dimensions, the pen would have a greater perimeter than the space, thus the pen could not measure 9ft by 22ft.

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The perimeter of a rectangle of length l and width w is given by:

$P = 2(l + w)$

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• The space has dimensions of 10 ft by 2''12ft = 12.17ft. Thus, the perimeter is, in feet:

$P = 2(10 + 12.17) = 2(22.17) = 44.34$

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• The pen, with dimensions of 9ft by 22ft, will have a perimeter, in feet, of:

$P = 2(9 + 22) = 2(31) = 62$

With these dimensions, the pen would have a greater perimeter than the space, thus the pen could not measure 9ft by 22ft.

A similar problem is given at brainly.com/question/10489198

Answer 2

“No; (9, 22) is a solution to the system of inequalities, but 22 ft is too long to fit in the space.”

i chose this answer choice and got points for it :)