Question

Nitrogen oxide racts with bromine to form nitrosyl bromide. A sample of 0.0655 mol NO with 0.0328 mol Br2 gives an equilibrium mixture containing 0.0389 mol NOBr. What is the composition of the equilibrum mixture?
2NO(g) + Br2(g) \leftrightarrow 2NOBr(g)

Answer 1

Answer:

NO = 0.0265 mol

Br₂ = 0.0133 mol

NOBr = 0.0389 mol

Explanation:

Let's consider the following reaction.

2 NO(g) + Br₂(g) ⇄ 2 NOBr(g)

We can find the composition at equilibrium using an ICE chart. Let x be an unknow amount.

         2 NO(g)    +    Br₂(g)    ⇄    2 NOBr(g)

I          0.0655        0.0328                 0

C           -2x                 -x                   +2x

E     0.0655 - 2x   0.0328 - x            2x

At equilibrium, the mixture contains 0.0389 mol NOBr. Then,

0.0389 mol = 2x

x = 0.0195 mol

The composition of the equilibrium mixture is:

NO = 0.0655 - 2x = 0.0265 mol

Br₂ = 0.0328 - x = 0.0133 mol

NOBr = 0.0389 mol