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jekas [21]
3 years ago
14

Cual es el calor específico de una sustancia que tiene una masa de 15 g y una capacidad térmica de 0.550 calC

Chemistry
1 answer:
mr Goodwill [35]3 years ago
6 0

Answer:

Explanation:

Q = Ce . m .ΔT

Q : calor  

Ce : calor especifico

m: masa  

ΔT : variación de temperatura

capacidad térmica : 0,550 cal / °C

lectura :

por 1 °C se tiene 0,550 cal

por lo tanto  tenemos datos de la temperatura y del calor

pero no olvidar las unidades en el sistema internacional :

Ce : J / kg . K

J: joules

kg: kilogramo

K: kelvin  

pasar de gramos a kilogramos

pasar de calorías a joules

pasar de grado celsius a kelvin

1000g equivale a 1kg

15g     equivale a 0,015 kg

K= °C + 273 ⇒ formula para pasar de grado celsius a kelvin

K=  1 + 273

K= 274

1 caloría equivale a  4,184 joules

0,550 caloría  equivale a 2,3012 joules

ahora como todos los datos ya están en el S.I remplazamos en la formula

Q = Ce . m .ΔT

2,3012 = Ce . 0,015.274

Ce=0,5599 J / kg. K

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What is the percentage yield of O2 if 12.3 g of KClO3 (molar mass 123 g) is decomposed to produce 3.2 g of O2 (molar mass 32 g)
My name is Ann [436]

Answer:

The percentage yield of O2 is 66.7%

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Reaction for decomposition of potassium chlorate is:

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The products are potassium chloride and oxygen.

Let's find out the moles of chlorate.

Mass / Molar mass = Moles

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Let's convert the moles of produced oxygen, as to find out the theoretical yield.

0.15 mol . 32 g/ 1mol = 4.8 g

To calculate the percentage yield, the formula is

(Produced Yield / Theoretical yield) . 100 =

(3.2g / 4.8g) . 100 = 66.7 %

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4 is true and 5 is false

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Hope this helped!

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2 years ago
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