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jekas [21]
3 years ago
14

Cual es el calor específico de una sustancia que tiene una masa de 15 g y una capacidad térmica de 0.550 calC

Chemistry
1 answer:
mr Goodwill [35]3 years ago
6 0

Answer:

Explanation:

Q = Ce . m .ΔT

Q : calor  

Ce : calor especifico

m: masa  

ΔT : variación de temperatura

capacidad térmica : 0,550 cal / °C

lectura :

por 1 °C se tiene 0,550 cal

por lo tanto  tenemos datos de la temperatura y del calor

pero no olvidar las unidades en el sistema internacional :

Ce : J / kg . K

J: joules

kg: kilogramo

K: kelvin  

pasar de gramos a kilogramos

pasar de calorías a joules

pasar de grado celsius a kelvin

1000g equivale a 1kg

15g     equivale a 0,015 kg

K= °C + 273 ⇒ formula para pasar de grado celsius a kelvin

K=  1 + 273

K= 274

1 caloría equivale a  4,184 joules

0,550 caloría  equivale a 2,3012 joules

ahora como todos los datos ya están en el S.I remplazamos en la formula

Q = Ce . m .ΔT

2,3012 = Ce . 0,015.274

Ce=0,5599 J / kg. K

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Calculate the molecular mass of N2O3​
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using the Bohr model for hydrogen: energy = hc/wavelength = 2.18 x 10^-18 Joules (1/nf2 - 1/ni2) N=15 to n=5
soldier1979 [14.2K]

Answer:

Energy lost is 7.63×10⁻²⁰J

Explanation:

Hello,

I think what the question is requesting is to calculate the energy difference when an excited electron drops from N = 15 to N = 5

E = hc/λ(1/n₂² - 1/n₁²)

n₁ = 15

n₂ = 5

hc/λ = 2.18×10⁻¹⁸J (according to the data)

E = 2.18×10⁻¹⁸ (1/n₂² - 1/n₁²)

E = 2.18×10⁻¹⁸ (1/15² - 1/5²)

E = 2.18×10⁻¹⁸ ×(-0.035)

E = -7.63×10⁻²⁰J

The energy lost is 7.63×10⁻²⁰J

Note : energy is lost / given off when the excited electron jumps from a higher energy level to a lower energy level

5 0
3 years ago
Given a magnesium value of 4.5mg/dL what is the result in SI units? gram atomic weight of Mg = 24
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Explanation:

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. Monthly measurements of atmospheric CO2 concentration at Mauna Loa began in March 1958. The average CO2 concentration for that
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Answer:

Increase=98.8ppm

Average\ increase/year=1.594\frac{ppm}{year}

Explanation:

Hello,

In this case, since the nowadays concentration of CO2 is 414.51 ppm and the concentration in 1958 was 315.71 ppm, the total increase is computed via the difference between them:

Increase=414.51ppm-315.71ppm\\\\Increase=98.8ppm

Moreover, the average increase per year is computed considering that from 1958 to 2020, 62 years have passed, therefore, such average is:

Average\ increase/year=\frac{98.8ppm}{62 years} \\\\Average\ increase/year=1.594\frac{ppm}{year}

Regards.

4 0
3 years ago
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