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3 years ago

Every single-celled organism is able to survive because it carries out *

Chemistry

1 answer:

deff fn [24]3 years ago

6 0

Answer:

Every single celled organism is able to survive because it carries out metabolic activities.

Metabolic activity is a set of chemical reactions which are needed for an organism to maintain it's life

Explanation:

the various types of metabolic processes keep an organism alive. There are various types of metabolic processes that takes place in the body of living organism.

These are cellular respiration, reproduction, excretion, digestion et cetera. Every living cell has these processes going on in their body to keep them alive.

Living organism need energy to carry out these processes which they get by eating food.

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Is Fe(OH)3 soluble

Gnom [1K]

No because all hydroxide salts are insoluble

3 0

3 years ago

Determine the correct amino acid sequence of a heptapeptide (a small peptide containing seven amino acids) on the basis of the f

vova2212 [387]

Answer:

a. Leu-Ala-Arg-Phe-Val-Val-Lys .

Explanation:

Hello.

In this case, considering the given data, we notice that the amino acid has a N-terminal Leu, that is why we first discard d. Moreover, considering the data (iii) and (v) we can infer that there are going to be two fragments by which it is possible to reason the proper sequence:

(iii): the amino acid has one section composed by Lys-Phe-Val-Val and another one by Ala, Arg, Leu that is why e is also discarded.

(v): the other two fragments are Ala, Arg, Leu, Phe, that is why b is discarded.

(iii) and (v): given the aforementioned fragments, we can combine them and therefore discard c, that is why the correct sequence is:

a. Leu-Ala-Arg-Phe-Val-Val-Lys .

Best regards.

4 0

3 years ago

Compounds X, C9H19Br, and Y, C9H19Cl, undergo base-promoted E2 elimination to give the same single alkene product, Z. Catalytic

Pavlova-9 [17]

Answer:

Compound X= 4-bromo-2,3,3-trimethylhexane

Compound Y= 5-chloro-2,3,3-trimethylhexane

Explanation:

The first step is set up the problem. That way we can obtain some clues. If we check figure 1 we can obtain some ideas:

-) If we have E2 reaction is not possible a methyl or hydride shift.

-) If we have an E2 reaction we will need an H in anti position to obtain the double bond. Therefore a double bond with the quaternary carbon (the carbon bonded to the 2 methyl groups).

The second step is to solve the alkene structure. We have to put the leaving group near to carbon that has more possible removable hydrogens. That's why the double bond is put it between carbons 5 and 4 of the alkane (Figure 2).

The third step is the structure of the alkyl bromide structure. To do this we have to check the alcohol produced by the alkene. In the hydration of alkanes reaction we will have a carbocation formation. Therefore we can have for the alkene proposed a methyl shift to obtain the most stable carbocation. With this in mind, we have to do the same for the Alkyl bromide that's why the Br is put it carbon 4 of the alkane. If we put the Br on this carbon we can have the chance of this methyl shift also, to obtain the same alcohol (figure 3).

Finally, for the alkyl chloride, we only have 2 choices because to produce the alkane we have to put the leaving group on one of the 2 carbons of the double bond. If we choose the same carbon on which we put the Br we can have the same behavior of the alkyl bromide (the methyl shift), therefore we have to put in the other carbon.

7 0

4 years ago

MgSO4(aq) + 2NaOH(aq) Mg(OH)2(s) + Na2SO4(aq) i. Write the complete ionic equation from the balanced equation. (3 points) Please

Igoryamba

Answer:

Mg²⁺(aq) + SO₄²⁻(aq) + 2Na⁺(aq) + 2OH⁻(aq) → Mg²⁺(aq) + 2OH⁻(s) + 2Na⁺(aq) + SO₄²⁻(aq)

Explanation:

The complete ionic equation is the chemical equation where the chemical species in the aqueous phase (aq) are written as ions.

In the reaction:

MgSO₄(aq) + 2NaOH(aq) → Mg(OH)₂(s) + Na₂SO₄(aq)

MgSO₄ dissociates in Mg²⁺ and SO₄²⁻, NaOH in Na⁺ and OH⁻, Mg(OH)₂ doesn't dissociate because is as solid and NaSO₄ dissociates in Na⁺ and SO₄²⁻ ions.

That means the complete ionic equation is:

4 0

3 years ago

Question 6

Alexxandr [17]

Answer:D

Explanation:

Metals are malleable

7 0

4 years ago