Ask question

Ask question

All categories

3 years ago

11

Simplify: 3 6 4 Help me out pls

1 answer:

Andreyy893 years ago

8 0

3 -> 1

6 -> 3 -> 1

4 -> 2 -> 1

i don't know

You might be interested in

In circle O, RV= 4 and VO= 7 find BA

Talja [164]

I think you will have t use theorem Ba=Rv^2+vo^2 Ba=4^2+7^2 Ba=16+49 Ba=65

4 0

4 years ago

1-m<br> ___ =2/3 HELP PLEASE<br> 1+m

marusya05 [52]

$Domain:\\\\1+m\neq0\to m\neq-1\\\\\dfrac{1-m}{1+m}=\dfrac{2}{3}\qquad\text{cross multiply}\\\\3(1-m)=2(1+m)\qquad\text{use distributive property}\\\\(3)(1)+(3)(-m)=(2)(1)+(2)(m)\\\\3-3m=2+2m\qquad\text{subtract 3 from both sides}\\\\-3m=-1+2m\qquad\text{subtract 2m from both sides}\\\\-5m=-1\qquad\text{divide both sides by (-5)}\\\\m=\dfrac{1}{5}\neq-1\\\\Answer:\ \boxed{m=\dfrac{1}{5}}$

7 0

4 years ago

Help? haha<br> solve the equation below:)<br> 3x - 5 = 10 + 2x

Setler [38]

Step-by-step explanation:

3x-2x=5+10 [taking variables on one side and constant on other]

x=15

soln:

3x-5= 2x+10

3x -5+5=2x+10+5 [ adding 5 on both side]

3x=2x+15

3x-2x=2x+15-2x [subtracting 2x on both side]

x=15

Ans=15

8 0

3 years ago

Read 2 more answers

State whether the following is perpendicular or parallel y=(1/2)×y=-2×+9

Rom4ik [11]

Answer:

parallel!

Step-by-step explanation:

if you insert the equation into demos there parallel

3 0

3 years ago

Fernell and Dabney shared the driving

Agata [3.3K]

Answer:

15 hours

Step-by-step explanation:

Given:

Fernell's speed $v_F= 50$ mph

Dabney's speed $v_D= 64$ mph

Denote:

$D_F$ - distance covered by Fernell

$D_D$ - distance covered by Dabney

$t_F$ - Fernell's time

$t_D$ - Dabney's time

1. If Fernell drove for 3 hours longer than Dabney, then his time is 3 hours more than Dabney's time and

$t_F=t_D+3$

2. If Fernell covered 18 miles less than Dabney, then

$D_D-D_F=18$

Use formula $D=t\cdot v$

$D_D=v_D\cdot t_D\Rightarrow D_D=64\cdot t_D\\ \\D_F=v_F\cdot t_F\Rightarrow D_F=50\cdot (t_D+3)$

Subtract from the first equation the second equation and equate it to 18:

$64t_D-50(t_D+3)=18\\ \\64t_D-50t_D-150=18\\ \\14t_D=168\\ \\t_D=12\ \text{hours}$

$t_F=t_D+3=12+3=15\ \text{hours}$

5 0

3 years ago