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anygoal [31]
3 years ago
10

histidine has three ionizable functional groups. complete the equilibrium equations by assigning the proper pKa for each ionizat

ion and the net charge on the histidine molecule in each ionization state.
SAT
1 answer:
charle [14.2K]3 years ago
6 0

Answer:

The equilibrium equations for the three ionizations in histidine with pK_{a} values are in attached document.

Hisidine has three ionizable functional group namely, the carboxylic group, amino group and nitrogen in the imidazole ring.

The structure of histidine in each ionization state is also attached.

Here, as from the attached diagrams the net charge in first, second and third  ionization state is  +1, 0 and -1 respectively.

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The digital sum of a 3-digit number is even if

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Count the number of 3-digit numbers, all of whose digits are even:

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• the second and third digits each have 5 options (2, 4, 6, 8, or 0)

So there are 4 × 5² = 100 such numbers.

Count the number of 3-digit numbers with 2 odd digits and 1 even digit:

• if the first digit is even, then there are 4 options (2, 4, 6, or 8), and the other two digits each have 5 options (1, 3, 5, 7, or 9)

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Swapping the second and third digits in the last case gets the same amount of numbers; we're effectively multiplying by the number of permutations of 2 objects taken 2 at a time, 2!.

So there are 4 × 5² + 2! × 5³ = 350.

Then there is a total of 450 3-digit numbers whose digital sums are even.

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