Answer:
The width of the border can be 9 feet or 3.5 feet.
Step-by-step explanation:
Let the width be x
Length of room = 10 feet
Breadth of room = 15 feet
Length of rug = 10-2x
Breadth of rug = 15-2x
Area of rug = 
We are given that the area of the rug is 24 square feet.
So, 
---A
Substitute x =9 in A
LHS = RHS
Substitute x = 3.5
LHS = RHS
So, The width of the border can be 9 feet or 3.5 feet.
The area of the ceiling:
A = 14² = 196 ft²
We need plaster to cover 196 ft².
196 : 90 = 2.17778
Answer: We have to buy 3 pails of plaster.
X/2-y/3=3/2
(6×x/2)-(6×y/3)=6×3/2
3x-2y=9______(1)
x/3+y/2=16/3
(6×x/3)+(6×y/2)=6×16/3
2x+3y=32_____(2)
(1)×3____9x-6y=27____(3)
(2)×2____4x+6y=64____(4)
(3)+(4)___13x=91
x=7
3(7)-2y=9
-2y=-12
y=6
Answer:
61
Step-by-step explanation:
to calculate the 20th term you use the formula
Tn=a+(n-1)d where a stands for the first term,n the number of terms and d the common difference.in this case the first term is 4 the common difference is 3 cause they were adding 3 to go to the next term.. therefore the solution will be:
Tn=4+(20-1)3
=4+19×3
=4+57
=61
the 20th term is 61
I hope this helps
Answer:
You can buy atleast 5 chicken sandwiches! (12 / 2.25 is 5.33333 (repeating))
