Question

Prove algebraically that the recurring decimal 0.35 (the 5 recurring) has the value 32%7D%7B90%7D" id="TexFormula1" title="\frac{32}{90}" alt="\frac{32}{90}" align="absmiddle" class="latex-formula">

Answer 1

Answer:

Step-by-step explanation:

r10 = 3.555555555...

r100 = 35.55555555...

then, r100-r10 = 35.555... - 3.555...

r90= 32

to find r, divide both sides by90

which will give as ;

r = 32

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90