Prove algebraically that the recurring decimal 0.35 (the 5 recurring) has the value

Question

2 years ago

15

32%7D%7B90%7D" id="TexFormula1" title="\frac{32}{90}" alt="\frac{32}{90}" align="absmiddle" class="latex-formula">

1 answer:

DedPeter [7] · Answer 1 · 2022-10-25T20:34:05+03:00

4 0

Answer:

Step-by-step explanation:

r10 = 3.555555555...

r100 = 35.55555555...

then, r100-r10 = 35.555... - 3.555...

r90= 32

to find r, divide both sides by90

which will give as ;

r = 32

------

90