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Mariana [72]
3 years ago
11

(2, 7) and (-6, -2) find the distance between each pair of points

Mathematics
1 answer:
yaroslaw [1]3 years ago
7 0

Answer:

\sqrt{145}

Step-by-step explanation:

Hi there!

We are given the points (2, 7) and (-6, -2). We want to find the distance between them. To do that, we can use the distance formula

The distance formula is given as \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}, where (x_1, y_1) and (x_2, y_2) are points

We have 2 points, which is what we need to find the distance, but let's label their values to avoid any confusion

x_1=2\\y_1=7\\x_2=-6\\y_2=-2

Now substitute those values into the formula:

\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

\sqrt{(-6-2)^2+(-2-7)^2}

Simplify the values under the radical:

\sqrt{(-8)^2+(-9)^2}

Raise to the second power:

\sqrt{64+81}

Add the numbers under the radical together

\sqrt{145}

The answer can be left as that, as the radical cannot be simplified.

Hope this helps!

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\begin{tabular}{| c | c | c |}\cline{1-3} Equation & x-intercepts & x-coordinate of vertex\\\cline{1-3} $y=x(x-2)$ & $x=0, x=2$ & $x=1$\\\cline{1-3} $y=(x-4)(x+5)$ & $x=-5, x=4$ & $x=-0.5$\\\cline{1-3} $y=-5x(x-3)$ & $x=0, x=3$ & $x=1.5$\\\cline{1-3} \end{tabular}

Step-by-step explanation:

x-intercepts are when the curve intercepts the x-axis, so when y =0.

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