3/4 + 2/3 = 1 5/12 eeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee
2 answers:
You might be interested in
Answer:
the guarantee period should be less than 136010 miles
Step-by-step explanation:
From the given information;
Let consider Y to be the life of a car engine
with a mean μ = 170000
and a standard deviation σ = 16500
The objective is to determine what should be the guarantee period T if the company wants less than 2% of the engines to fail.
i.e
P(Y < T ) < 0.02
For the variable of z ; we have:
Now;
From Z table ;
At P(Z < -2.06) ≅ 0.0197 which is close to 0.02
Thus; the guarantee period should be less than 136010 miles