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Virty [35]
2 years ago
15

Some jobs pay a commission plus a bonus at the end of the year. The bonus may be a percent of the salesperson's total commission

for the year. a. Madelyn Carr is a sales representative. She receives 7 percent commission on all sales. At the end of the year, she receives a bonus of 5 percent of her commission. What is her total pay for a year in which she had sales totaling $412,454? b. What would Carr's total pay be if her sales were $316,250?​
Mathematics
1 answer:
Zarrin [17]2 years ago
5 0

Answer:

Step-by-step explanation:

commision the end of the year is;

7

------- × 412454

100

= $28871.78

bonus is ;

5

--------- × 28871.78

100

= 1443.589

total pay is 1443.589 + 28871.78

= $30315.369.

(b)

5

----------- × 316250

100

= $15812.5

total pay is = 15812.5 + 316250

= $332062.5

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lin is 5 inches taller than her cousin mai. together their heights are 113 inches. how tall is each girl
elena-14-01-66 [18.8K]

First, lets take away 5 inches from 113                113 - 5 =  108

Now that have 108, let's split that in half so it can be each of the girls' height.

108 ÷ 2 = 54

So, both girls are 54 inches in height.

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3 years ago
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What is the midpoint between (-4 - 2i) and ( 6 + 8i) on the complex plane?
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Add the real parts and the imaginary parts separately and divide each by 2


= (  \frac{ - 4 + 6}{2}  +   \frac{ - 2i + 8i}{2} )


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2 years ago
The data given to the right includes data from ​candies, and of them are red. The company that makes the candy claims that ​% of
Dafna1 [17]

Using the z-distribution, the 95% confidence interval for the percentage of red candies is of (7.84%, 33.18%). Since 33% is part of the interval, there is not enough evidence to conclude that the claim is wrong.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which:

  • \pi is the sample proportion.
  • z is the critical value.
  • n is the sample size.

In this problem, we have a 95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so the critical value is z = 1.96.

Researching this problem on the internet, 8 out of 39 candies are red, hence the sample size and the estimate are given by:

n = 39, \pi = \frac{8}{39} = 0.2051

Hence the bounds of the interval are:

  • \pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2051 - 1.96\sqrt{\frac{0.2051(0.7949)}{39}} = 0.0784
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As a percentage, the 95% confidence interval for the percentage of red candies is of (7.84%, 33.18%). Since 33% is part of the interval, there is not enough evidence to conclude that the claim is wrong.

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

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