A Suppose 13-year and 17-year cicadas both appear this year. When will both
1 answer:
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Answer:
y =
Step-by-step explanation:
Let the total numbers are n.
If the average of y numbers is x then we can form an equation
⇒
⇒ n = --------(1)
Now 30 is added to the set of numbers then average becomes (x - 5)
⇒
⇒ (n + 1) =
⇒ n = - 1 ----- (2)
Now we equate the values of n from equation 1 and 2
=
- 1
y(x - 5) = x(y + 30) - x(x - 5) [ By cross multiplication ]
xy - 5y = xy + 30x - x² + 5x
xy - xy - 5y = 35x - x²
-5y = 35x - x²
x² - 35x = 5y
y =
Answer:
Step-by-step explanation:
<u>Solving</u> :
⇒ log y = log (x²)
⇒ log y = 2 log x
⇒
⇒