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2 years ago

A hot air balloon descended 3,240 feet in an hour. find the change in altitude per minute.

Mathematics

1 answer:

3241004551 [841]2 years ago

4 0

Answer:

-54ft/min (-54 feet per minute)

Step-by-step explanation:

To solve this, we need to use background knowledge to get one of our missing numbers.

Since we know an hour is 60 minutes, we need to do 3,240/60 to receive our unit rate. So, 3,240/60 would equal 54.

But, the balloon is <u>descending</u> (going down), so we need to make our answer negative (54 -> -54)

Therefore, the hot air balloon is descending 54 feet per minute, or -54ft/min.

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A number, n, is greater than 22.

AnnyKZ [126]

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3 years ago

Need help with this question

Elenna [48]

The sum of adjacent angles on a straight line would be 180°.

Since x is on a straight line,what we need to do is to deduct the remaining two angles,here's what the equation would be like:

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2 years ago

Read 2 more answers

The annual precipitation amounts in a certain mountain range are normally distributed with a mean of 104 inches, and a standard

dsp73

Answer:

91.92% probability that the mean annual precipitation during 49 randomly picked years will be less than 106.8 inches

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sample means with size n of at least 30 can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$

In this problem, we have that:

$\mu = 104, \sigma = 14, n = 49, s = \frac{14}{\sqrt{49}} = 2$

What is the probability that the mean annual precipitation during 49 randomly picked years will be less than 106.8 inches

This is the pvalue of Z when X = 106.8. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{106.8 - 104}{2}$

$Z = 1.4$

$Z = 1.4$ has a pvalue of 0.9192

0.9192 = 91.92% probability that the mean annual precipitation during 49 randomly picked years will be less than 106.8 inches

8 0

3 years ago

WIll give brainliest Use the information given to answer the question.

MaRussiya [10]

Answer:

x²-12x+36

Step-by-step explanation:

an expression in the form (a-b)² is expanded to the form a²-2ab+b²

you can also expand it to (x-6)×(x-6) then multiply the first term by the first the outer term by the outer term the inner term by the inner term and the last term by the last term (foil)

the first terms are x and x = x² the outer terms are x and -6 = -6x the inner terms are also x and -6 = -6x

the last terms are 6 and 6 = 36

adding all the four products =

x²-12x+36

7 0

2 years ago

Plz answer the following file attached

Finger [1]

Answer:

i like how to tell us to answer something with no file

Step-by-step explanation:

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2 years ago