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3 years ago

Let A = Aaron's age today and M = Maria's age today.

Mathematics

1 answer:

kondor19780726 [428]3 years ago

3 0

Aaron is 4 years and Maria is 14 years old.

A = Aaron's age today

M = Maria's age today.

a. The equation based on the statement given will be:

M = A + 10

b. Maria's age based on the statement in 6 years will be:

= (A + 10) + 6

= A + 16

c. Based on the information above, the equation to solve their ages will be:

A + 16 = 2(A + 6)

A + 16 = 2A + 12

Collect like terms

2A - A = 16 - 12

A = 4

Therefore, Aaron is 4 and Maria is 14 years.

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Step-by-step explanation:

We know that

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$\mathrm{Cancel\:}\frac{10}{15}:\quad \frac{2}{3}$

$=\frac{2}{3}-\frac{2}{5}$

$\mathrm{Least\:Common\:Multiplier\:of\:}3,\:5:\quad 15$

$\mathrm{Adjust\:Fractions\:based\:on\:the\:LCM}$

$\mathrm{For}\:\frac{2}{3}:\:\mathrm{multiply\:the\:denominator\:and\:numerator\:by\:}\:5$

$\frac{2}{3}=\frac{2\cdot \:5}{3\cdot \:5}=\frac{10}{15}$

$\mathrm{For}\:\frac{2}{5}:\:\mathrm{multiply\:the\:denominator\:and\:numerator\:by\:}\:3$

$\frac{2}{5}=\frac{2\cdot \:3}{5\cdot \:3}=\frac{6}{15}$

$=\frac{10}{15}-\frac{6}{15}$

$\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}$

$=\frac{10-6}{15}$

$\mathrm{Subtract\:the\:numbers:}\:10-6=4$

$=\frac{4}{15}$

Therefore,

$\frac{10}{15}-\frac{2}{5}=\frac{4}{15}$

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