last one
Step-by-step explanation:
3 1/2
answer is last one
For a 30 sided regular polygon, We can divide the polygon (30 sides) into 30 inscribed triangles with central vertex angles of = 
.
This central vertex angle of <u>12 degrees</u> is the degree of rotation for a 30 sided polygon.
In other words, the 30 sided polygon has <u>12 degree</u> rotational symmetry about the center.
<span>k+12/k=8
Multiply k to remove the k in one side
</span><span>(k+12/k=8) (k)
</span>Therefore,
k^2+12k-8k=0
Thus,
The equations he must solved now is k^2-8+12=0
Step-by-step explanation:
solution
let,A(5,-1)
given
y=12x-1
or, y = 12 × x + (-1)
comparing it with y=mx+c
we get
x=1
y = c = -1
now
A(5,-1) and B(1,-1)
equation of line is,
(y-y1)/(x-x1) = (y2-y1)/(x2-x1)
or, (y+1)/(x-5) = (-1+1)/(1-5)
or, (y+1)/(x-5) = 0/-4
cross multiply
-4y-4 = 0
or, 0=4y+4
or, 4y+4=0 is the required eqn
I think this is the process and answer too.
I hope this helps you
