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barxatty [35]
3 years ago
15

What number should go in the space? Multiplying by 1.75 is the same as increasing by _____%.

Mathematics
1 answer:
chubhunter [2.5K]3 years ago
3 0

Answer:75%

Step-by-step explanation:

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Explain how the common difference in an arithmetic sequence is like the slope of a linear function. read more >>
faust18 [17]
In arithmetic sequence, let the first tern of the arithmetic sequence be, a, and the common difference, d, then the nth term, Tn, of the arithmetic sequence is given by:

T_n=a+(n-1)d

For a linear function with y-intercept, c, and slope, m, the linear function is given by:

y=mx+c

Comparing the equation of the arithmetic sequence and that of the linear function, we can see that y is compared to Tn, a is compared to c, m is compared to d, and x is compared to n - 1.

Therefore, <span>the common difference in an arithmetic sequence is like the slope of a linear function as both are multiple of a variable.</span>
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3 years ago
2. The Andersons went to dinner at
irina1246 [14]
They left $6.72 for a tip.

42 x 0.16 = 6.72
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3 years ago
To bake one cake, Drew uses 18 ounces of flour. He has 850 ounces of flour. Let y represent the ounces of flour left and x repre
egoroff_w [7]
Y= 850-18x
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5 0
3 years ago
Read 2 more answers
An urn contains 5 red balls and 2 green balls. Two balls are drawn one after the other. What is the probability that the second
AleksAgata [21]

Answer:

<em>The probability that the second ball is red is 71%</em>

Step-by-step explanation:

<u>Probabilities</u>

We know there are 5 red balls and 2 green balls. Let's analyze what can happen when two balls are drawn in sequence (no reposition).

The first ball can be red (R) or green (G). The probability that it's red is computed by

\displaystyle P(R)=\frac{5}{7}

The probability is's green is computed by

\displaystyle P(G)=\frac{2}{7}

If we have drawn a red ball, there are only 4 of them out of 6 in the urn, so the probability to draw a second red ball is

\displaystyle P(RR)=\frac{5}{7}\cdot \frac{4}{6}=\frac{10}{21}

If we have drawn a green ball, there are still 5 red balls out of 6 in the urn, so the probability to draw a red ball now is

\displaystyle P(GR)=\frac{2}{7}\cdot \frac{5}{6}=\frac{5}{21}

The total probability of the second ball being red is

\displaystyle P(XR)=\frac{10}{21}+\frac{5}{21}=\frac{5}{7}=0.71

The probability that the second ball is red is 71%

7 0
3 years ago
If 5|x − 1| = 20, then x = <br> 1 or 5<br> 6 or –8<br> –2 or 4<br> 5 or –3<br> Please help
anygoal [31]

Answer:

Step-by-step explanation:

5 0
3 years ago
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