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2 years ago

Select the true statement about the diagram.

1 answer:

5 0

Answer:

The answer is A, It shows an exothermic overall reaction.

Explanation:

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OlgaM077 [116]

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3 years ago

tresset_1 [31]

Answer: 4.5 moles of $H_{2}$ can be made from complete reaction of 3.0 moles of Al.

Explanation:

The given reaction equation is as follows.

$2Al + 6HCl \rightarrow 2AlCl_{3} + 3H_{2}$

This shows that 2 moles of Al reacts with 6 moles of HCl. So, the amount of HCl required to react with 1 mole Al is three times the amount of HCl.

Therefore, 3 moles of Al will react with 9 moles of HCl to give 3 moles of $AlCl_{3}$ and $\frac{9}{2}$ moles of $H_{2}$ .

The reaction equation now will be as follows.

$3Al + 9HCl \rightarrow 3AlCl_{3} + \frac{9}{2}H_{2}$

The moles $\frac{9}{2}$ can also be written as 4.5 moles.

Thus, we can conclude that 4.5 moles of $H_{2}$ can be made from complete reaction of 3.0 moles of Al.

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2 years ago

alexandr402 [8]

The Lewis acids are electron pair acceptors due to the availability of vacant orbitals they accept electrons from the donor compounds.

$(CH_3CH_2)_2CH^{+}$ is a Lewis acid due to the unfilled valence shell on carbon atom (possessing positive charge) it accepts electron readily.
$CCl_{3}^{-}$ is not a Lewis acid due to the presence of negative charge which represents that there are electrons available for donation.
$CH_3NH_2$ is not a Lewis acid due to the presence of lone pair on nitrogen which is easily donated to the acceptors.
$BBr_3$ is a Lewis acid due to the availability of vacant p-orbital on boron atom.

Hence, $(CH_3CH_2)_2CH^{+}$ and $BBr_3$ are Lewis acids.

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3 years ago

Olegator [25]

Answer: B then D

Explanation:

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3 years ago