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vagabundo [1.1K]

3 years ago

5

If there are no changes in the oxidation state of the reactants or products of a particular reaction, that reaction is not a red

ox reaction.

1 answer:

dmitriy555 [2]3 years ago

3 0

Yes, that is true. in order for it to be a redox reaction, both oxidation and reduction must be occurring.

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True or false a contour line indicates that all points on that line have equal elevation

Helga [31]

True. Each contour line on a topographic map represent a certain elevation; the closer they are, the steeper the surface is. All points on a contour line are the same elevation.

3 0

3 years ago

The concentration of dye in Solution A is 26.609 M. You have 13 mL of water at your disposal to make the dilutions. The solution

exis [7]

Answer:

6,613 M

Explanation:

Dilution is the process of reducing the concentration of a solute in solution, mixing initial solution with more solvent.

The concentration of Solution B is:

23,881 M × = 9,552 M

Because the initial eight parts are diluted to 12+8 parts.

Thus, concentration of solution C is:

9,552 M × = 6,613 M

I hope it helps!

8 0

2 years ago

How many orbitals surround the nucleus in a neutral atom of sulfur (S)?

Leto [7]

<h2>C</h2>

Explanation:

The atomic number of S is $16$

So,number of electrons in S is $16$

The electronic configuration of S is $2,8,6$

The orbital electronic configuration of S is $^{1}s_{2}^\text{ }^{2}s_{2}^\text{ }^{2}p_{x2}^\text{ }^{2}p_{y2}^\text{ }^{2}p_{z2}^\text{ }^{3}s_{2}^\text{ }^{3}p_{x2}^\text{ }^{3}p_{y1}^\text{ }^{3}p_{z1}^\text{ }$

So,the number of orbitals involved is 9.

3 0

2 years ago

How many moles are in a 62.5-g sample of potassium nitrate (KNO3)?

Reil [10]

Answer:25.3 g of KNO₃ contain 0.25 moles.

Explanation:

7 0

2 years ago

Calculate the mass of Na2O that can be produced by the chemical reaction of 4.0 grams of sodium with excess oxygen in the reacti

e-lub [12.9K]

Answer:

The mass of Na₂O that can be produced by the chemical reaction of 4.0 grams of sodium with excess oxygen in the reaction is 5.39 grams.

Explanation:

You know the balanced reaction:

4 NA + O₂ ⟶ 2 Na₂O

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction) react and are produced:

Na: 4 moles
O₂: 1 mole
Na₂O: 2 moles

Being:

Na: 23 g/ole
O: 16 g/mole

the molar mass of the compounds participating in the reaction is:

Na: 23 g/mole
O₂: 2*16 g/mole= 32 g/mole
Na₂O: 2*23 g/mole +16 g/mole= 62 g/mole

Then by stoichiometry of the reaction they react and are produced:

Na: 4 moles* 23 g/mole= 92 g
O₂: 1 mole*32 g/mole= 32 g
Na₂O: 2 moles* 62 g/mole= 124 g

Then you can apply the following rule of three: if 92 grams of Na produce 124 grams of Na₂O, 4 grams of Na, how much mass of Na₂O does it produce?

$massofNa_{2}O =\frac{4 grams of Na*124 gramsofNa_{2}O }{92 grams of Na}$

mass of Na₂O=5.39 g

<em><u>The mass of Na₂O that can be produced by the chemical reaction of 4.0 grams of sodium with excess oxygen in the reaction is 5.39 grams.</u></em>

8 0

2 years ago