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vagabundo [1.1K]

3 years ago

5

If there are no changes in the oxidation state of the reactants or products of a particular reaction, that reaction is not a red

ox reaction.

1 answer:

dmitriy555 [2]3 years ago

3 0

Yes, that is true. in order for it to be a redox reaction, both oxidation and reduction must be occurring.

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Which of the following statements is true? A) This reaction will be spontaneous only at high temperatures. B) This reaction will

viktelen [127]

Answer:

D) This reaction will be nonspontaneous only at high temperatures.

Explanation:

According the equation of Gibb's free energy -

∆G = ∆H -T∆S

∆G = is the change in gibb's free energy

∆H = is the change in enthalpy

T = temperature

∆S = is the change in entropy .

And , the sign of the ΔG , determines whether the reaction is Spontaneous or non Spontaneous or at equilibrium ,

i.e. ,

if

ΔG < 0 , the reaction is Spontaneous

ΔG > 0 , the reaction is non Spontaneous

ΔG = 0 , the reaction is at equilibrium

The reaction has the value for ∆H = negative , and ∆S = negative ,

Now ,

∆G = ∆H -T∆S

= ( - ∆H ) - T( - ∆S )

= ( - ∆H ) +T( ∆S )

Now, for making the reaction Spontaneous ΔG = negative ,

Hence ,

The temperature is low, then the value for ΔG will be negative , i.e. , Spontaneous reaction .

And , vice versa , at higher temperature , the reaction will have ΔG positive , and the reaction will be non -Spontaneous reaction .

The standard free energy of formation will be zero , only for the compounds that are in their pure form ,

Hence , Al(s) will have ΔG = 0 .

7 0

3 years ago

12345 [234]

Answer) All of the above

7 0

2 years ago

Read 2 more answers

Calculate the mass in 4.05*10^22 molecules of calcium phosphate

Marizza181 [45]

Answer:

m = 20.9 g.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to solve this problem by recalling both the Avogadro's number for the calculation of the moles in the given molecules of calcium phosphate and the molar mass of this compound in order to secondly calculate the mass as shown on the following setup:

$m=4.05x10^{22}molecules*\frac{1mol}{6.022x10^{23}}*\frac{310.18g}{1mol}\\\\m=20.9g$

Regards!

8 0

2 years ago

How do forensic scientists determine the time of death? There are timely pieces of evidence that help scientists with this task.

UNO [17]

I have done some research as well as asking some friends. This is what I came up with. Not sure if it is 100% correct.

step = time after death

1. Livor Mortis = 20-30 minutes

2. Eyes film (cloud) = 2 hours

3. Rigor Mortis begins = 4-6 hours

4. Empty small intestines = 12 hours

5. Bloating = 3-5 days

6. Decay

8 0

3 years ago

Using only the 1h nmr spectrum of the crude nitration product, determine if the product is mostly ortho-, meta-, or para- substi

tatiyna

<span>The nitartion of methyl benzoate is expected to proceed as given in the equation below:

</span>

In methyl benzoate there are 3 types of 1 H proton. The two ortho to the C=O group is a doublet at 8 ppm the 2 metal to the C=O is a multiple at 7.5 ppm and one para to the C=O is a multiplet at 7.5 ppm.

On nitration the ortho will probably show two signal one being a single with 3 proton integration and one a doublet with 1 H integration

The meta will show a highly down field singlet (coresponding to 1 proton), two unequal doublets (corresponding to 1 H each) and one multiplets (corresponding to 1H). This is the major product as seen from the 1H NMR.

The para isomer will come as two doublets which will be very close to each other there is a small signal for this set between 8.2 and 8.3 ppm.

7 0

3 years ago