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SashulF [63]
3 years ago
6

How many sig figs are in 0.006 0.0605 60.5 605.5 960 x 10^-3 6 60

Chemistry
1 answer:
bija089 [108]3 years ago
3 0


1

3

3

4

3

1

1

are the answers respectively...

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For Mn3+, write an equation that shows how the cation acts as an acid.
Mkey [24]

An acid is a compound which will give H+ ions or H3O^+  ions

the reaction will be

[Mn(H_{2}O )_{6} ^{+3} +H_{2}O --> [MnOH(H_{2}O)_{5}]^{+2} + H_{3}O^{+}

Thus as there is evolution of H_{3}O^{+} the Mn+3 is an acid

8 0
3 years ago
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Dioxin is a by-product of various industrial chemical processes. It is suspected of causing cancer and birth defects in both hum
Nuetrik [128]

Answer:

The natural ligand of the cytosolic Aryl hydrocarbon receptor which is still not known.

Explanation:

Dioxin is formed during some industrial chemical processes. It is considered harmful because it causes cancer, weakens the immune system, results in nervous breakdown and also affects reproduction.

The mechanism of operation of Dioxins has not been fully understood. However, it is known that dioxins works through a receptor known as the Aryl hydrocarbon receptor. This receptor is useful in gene expression and also acts as a transcription factor.

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3 years ago
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A brick measures 25 cm by 12 cm by 13 cm. What is the volume of the brick in cm3? How many milliliters of water would this brick
hodyreva [135]
Volume is lxwxh so do 25x12x13
7 0
4 years ago
Cual es la flora de los Bancos Aluviales?<br>Por favor necesito ayuda
Wewaii [24]

Answer:

Un río aluvial es aquel en el que el lecho y las riberas están formados por sedimentos móviles y / o suelo.

Explanation:

3 0
3 years ago
A) Find the gas speed of sulfur dioxide at 100.0 degrees Celsius? ______________
gtnhenbr [62]

a. 381.27 m/s

b. the rate of effusion of sulfur dioxide = 2.5 faster than nitrogen triiodide

<h3>Further explanation</h3>

Given

T = 100 + 273 = 373 K

Required

a. the gas speedi

b. The rate of effusion comparison

Solution

a.

Average velocities of gases can be expressed as root-mean-square averages. (V rms)  

\large {\boxed {\bold {v_ {rms} = \sqrt {\dfrac {3RT} {Mm}}}}

R = gas constant, T = temperature, Mm = molar mass of the gas particles  

From the question  

R = 8,314 J / mol K  

T = temperature  

Mm = molar mass, kg / mol  

Molar mass of Sulfur dioxide = 64 g/mol = 0.064 kg/mol

\tt v=\sqrt{\dfrac{3\times 8.314\times 373}{0.064} }\\\\v=381.27~m/s

b. the effusion rates of two gases = the square root of the inverse of their molar masses:  

\rm \dfrac{r_1}{r_2}=\sqrt{\dfrac{M_2}{M_1} }

M₁ = molar mass sulfur dioxide = 64

M₂ =  molar mass nitrogen triodide = 395

\tt \dfrac{r_1}{r_2}=\sqrt{\dfrac{395}{64} }=\dfrac{20}{8}=2.5

the rate of effusion of sulfur dioxide = 2.5 faster than nitrogen triodide

4 0
3 years ago
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