Answer:
100 mL
Explanation:
Given data:
Mass of CaCO₃ produced = 2.00 g
Molarity of CaCl₂ = 0.200 M
Volume of CaCl₂ needed = ?
Solution:
Chemical equation:
Na₂CO₃ + CaCl₂ → 2NaCl + CaCO₃
First of all we will calculate the number of moles of CaCO₃.
Number of moles = mass/molar mass
Number of moles = 2.00 g / 100.09 g/mol
Number of moles = 0.02 mol
Now we will compare the moles of CaCO₃ and CaCl₂.
CaCO₃ : CaCl₂
1 : 1
0.02 : 0.02
Thus, 0.02 moles of CaCl₂ react,
Volume of CaCl₂ reacted:
Molarity = number of moles / volume in L
0.200 M = 0.02 mol / volume in L
Volume in L = 0.02 mol / 0.200 M
Volume in L = 0.1 L
Volume in mL:
0.1 L × 1000 mL/1L
100 mL
Answer:
1.09 x 10²⁴ atoms Na
Explanation:
In one mole of NaCl, there is also one mole of Na. To convert between moles and atoms, you need to use Avogadro's number. When writing the conversion, the desired unit (atoms) should be placed in the numerator to allow for the cancellation of units (moles). The final answer should have 3 sig figs to match the given number (1.81 mole).
Avogadro's Number:
6.022 x 10²³ atoms = 1 mole
1.81 moles Na 6.022 x 10²³ atoms
--------------------- x -------------------------------- = 1.09 x 10²⁴ atoms Na
1 mole
Answer:
X = 4
Explanation:
Start 2800
End 175
175 = 2800x(0.5)^X
175/2800 = 0.5^X
0.0625 = 0.5^X
log(0.5 x) = log(0.0625)
x · log(0.5) = log(0.0625)
-0.301x = -1.204
x = -1.204/-0.301
x = 4
Answer:
2.5 moles of KOOH are produced.
Explanation:
1)Given data:
Number of moles of KOOH produced = ?
Number of moles of LiClO = 5 mol
Solution:
Chemical equation:
2LiClO + KHSO₄ → Li₂SO₄ + Cl₂ + KOOH
now we will compare the moles of KOOH and LiClO.
LiClO : KOOH
2 : 1
5 : 1/2×5 = 2.5
2.5 moles of KOOH are produced.
Answer:
Chemical energy
Explanation:
When the body eats food our bodies convert the stored energy (calories) to chemical energy, allowing us to function.
