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Nostrana [21]
3 years ago
10

Determine the formal charges on the highlighted atoms. if an atom is formally neutral, indicate a charge of zero.the molecule h

3 c c n o. the second c is connected to the c h 3 group with a single bond and to n with a triple bond. n is highlighted and is connected to c with a triple bond and o with a single bond. o is highlighted and is connected to n with a single bond and has 3 lone pairs of electrons.
Chemistry
1 answer:
Deffense [45]3 years ago
7 0

Answer:

Formal charge on n is +1

Formal charge on o is -1

Explanation:

Consider the atom n,

n is connected to o with a single bond and to c with a triple bond

<h3>Formula for formal charge on an atom is number of valence electrons - number of non-bonding electrons - (number of bonding electrons) ÷ 2</h3>

In case of n, number of valence electrons are 5

Number of non-bonding electrons are 0

Number of bonding electrons are 8 (∵ n is attached to 4 bonds and each bond is equivalent to 2 electrons)

∴ Formal charge on n = 5 - 0 - (8 ÷ 2) = 5 - 4 = +1

∴ Formal charge on n is +1

Consider the atom o,

o is connected to n by a single bond

In case of o, number of valence electrons are 6

Number of non-bonding electrons are 6 (∵ it has 3 lone pair of electrons)

Number of bonding electrons are 2 (∵ it is connected to n by a single bond and that bond is equivalent to 2 electrons)

Formal charge on atom o = 6 - 6 - (2 ÷ 2) = -1

∴ Formal charge on o is -1

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3 years ago
A solution contains one or more of the following ions: Ag+, Ca2+, and Co2+. Lithium bromide is added to the solution and no prec
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<h3>Answer:</h3>

#1. Ca²⁺

# 2. Ca²⁺(aq) + SO₃²⁻(aq) → CaSO₄(s)

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<h3>Explanation:</h3>

The question above concerns solubility of salts or ions in water.

The solution given contains Ag+, Ca2+, and Co2+ ions.

  • In the first case, when Lithium bromide is added to the solution, there is no white precipitate formed.
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  • From the solubility rules, all sulfates are soluble except BaSO₄, CaSO₄, and PbSO₄.
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