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Nata [24]
3 years ago
6

Use the graph to estimate the value of y when x = 2.5​

Mathematics
1 answer:
WINSTONCH [101]3 years ago
8 0

Answer:

7 ish

Step-by-step explanation:

if you look at where 2.5 would be on the X axis (in-between 2 and 3) and you look at the corresponding Y point, its somewhere near where 7 would be.

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Name two rays that contain the following line segments: • QP• SU (the options for QP are: rays PU; QP; TQ; NP; MS)(the options f
julsineya [31]

From the figure, segment QP is in the ray RP and RP contains N and Q in between

so from the options, the two rays will be : ray QP and ray NP

For SU :

segment SU is in the ray RU and RU contains S and T in between,

so from the options again, the two rays will be : ray RU and ray SU

5 0
1 year ago
Solve the following equation:<br> V= 2(ab+bc+ca), for a
Nadya [2.5K]

V = 2ab + 2ca + 2bc

2ab + 2ca = V - 2bc

2a * b + c = V - 2bc

Answer: a = v - 2bc / 2 * b + c



Hope that helps!!!!! : )

8 0
3 years ago
Use the law of cosines to find the indicated missing side
max2010maxim [7]

Answer:

19.08

Step-by-step explanation:

c² = a² + b² - 2ab×cos(C)

a=10

b=22

C=60

cos(60) = 0.5

c² = 10² + 22² - 2×10×22×cos(60) =

= 100 + 484 - 20×22×0.5 = 584 - 20×11 = 584 - 220 =

= 364

c = sqrt(364) ≈ 19.08

7 0
2 years ago
F ind the volume under the paraboloid z=9(x2+y2) above the triangle on xy-plane enclosed by the lines x=0, y=2, y=x
olga nikolaevna [1]

Answer:

The answer is 48 units³

Step-by-step explanation:

If we simply draw out the region on the x-y plane enclosed between these lines we realize that,if we evaluate the integral the limits all in all cannot be constants since one side of the triangular region is slanted whose equation is given by y=x. So the one of the limit of one of the integrals in the double integral we need to evaluate must be a variable. We choose x part of the integral to have a variable limit, we could well have chosen y's limits as non constant, but it wouldn't make any difference. So the double integral we need to evaluate is given by,

V=\int\limits^2_0 {} \, \int\limits^{x=y}_0 {z} \, dx dy\\V=\int\limits^2_0 {} \, \int\limits^{x=y}_0 {9(x^{2}+y^{2})} \, dx dy

Please note that the order of integration is very important here.We cannot evaluate an integral with variable limit last, we have to evaluate it first.after performing the elementary x integral we get,

V=9\int\limits^2_0 {4y^{3}/3} \, dy

After performing the elementary y integral we obtain the desired volume as below,

V= 48 units^{3}

4 0
2 years ago
You have 50$ to spend at the carnival. First, you must pay $9.20 for an entrance ticket. Each snack costs $4.25, including tax.
asambeis [7]
50 - 9.20 = 40.80 so 40.80/ 4.25 = 9.6 but you can’t buy .6 of a snack so it’s 9
5 0
3 years ago
Read 2 more answers
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