From the figure, segment QP is in the ray RP and RP contains N and Q in between
so from the options, the two rays will be : ray QP and ray NP
For SU :
segment SU is in the ray RU and RU contains S and T in between,
so from the options again, the two rays will be : ray RU and ray SU
V = 2ab + 2ca + 2bc
2ab + 2ca = V - 2bc
2a * b + c = V - 2bc
Answer: a = v - 2bc / 2 * b + c
Hope that helps!!!!! : )
Answer:
19.08
Step-by-step explanation:
c² = a² + b² - 2ab×cos(C)
a=10
b=22
C=60
cos(60) = 0.5
c² = 10² + 22² - 2×10×22×cos(60) =
= 100 + 484 - 20×22×0.5 = 584 - 20×11 = 584 - 220 =
= 364
c = sqrt(364) ≈ 19.08
Answer:
The answer is 48 units³
Step-by-step explanation:
If we simply draw out the region on the x-y plane enclosed between these lines we realize that,if we evaluate the integral the limits all in all cannot be constants since one side of the triangular region is slanted whose equation is given by y=x. So the one of the limit of one of the integrals in the double integral we need to evaluate must be a variable. We choose x part of the integral to have a variable limit, we could well have chosen y's limits as non constant, but it wouldn't make any difference. So the double integral we need to evaluate is given by,

Please note that the order of integration is very important here.We cannot evaluate an integral with variable limit last, we have to evaluate it first.after performing the elementary x integral we get,

After performing the elementary y integral we obtain the desired volume as below,

50 - 9.20 = 40.80 so 40.80/ 4.25 = 9.6 but you can’t buy .6 of a snack so it’s 9