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2 years ago

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Zeus Industries bought a computer for $2207. It is expected to depreciate at a rate of 27% per year. What will the value of the

computer be in 4 years? Round to the nearest penny. Do not type the "$" sign in your answer

1 answer:

shepuryov [24]2 years ago

5 0

2,207×(1−0.27)^(4)
=626.75

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Tiana looks at a map to find the best route from her house to her friend's house. the map has a scale of 4 centimeters = 3 miles

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Answer: 6

Step-by-step explanation:

4 centimeters times what gives u 8 centimeters

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2 years ago

2x-4y=-20 write it in y=ax+b form

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Answer:

$y = \frac{1}{2} x + 5$

Step-by-step explanation:

$2x - 4y = - 20 \\ \\ - 4y = - 2x - 20 \\ \\ y = \frac{ - 2}{ - 4}x - \frac{20}{ - 4} \\ \\ y = \frac{1}{2} x + 5$

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2 years ago

A tiny songbird called the blackpoll warbler migrates each fall from North America. A tracking study showed one bird flew from V

Alexus [3.1K]

Answer:

<h3>2642km</h3>

Step-by-step explanation:

Given the map coordinates o a bird during travel from Vermont at cordinate (63,45) toto Venezuela at map coordinates (67,10). In order to know how far the bird has travelled, we need to find the distance between the two coordinates first using the formula;

D = $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Given x₁ = 63, y₁ = 45, x₂ = 67, y₂ = 10

$D =\sqrt{(67-63)^2+(10-45)^2}\\ \\D = \sqrt{4^2+(-35)^2} \\\\D = \sqrt{16+1225} \\\\D = \sqrt{1241} \\\\D = 35.2278$

If each map coordinate represents 75 kilometers, then the birds distance in km will be 75*35.2278 = 2642.087km

Hence the birds distance in km will be 2642km to the nearest kilometers

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2 years ago

A car takes 4 hours to cover a certain distance, travelling at a speed of 120 km/h. How long will the car take if it travels at

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3/8 hours

Step-by-step explanation:

distance=speed/time=120/4=30km

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2 years ago

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For what value(s) of k is the linear system consistent? (Enter your answers as a comma-separated list.)

AleksAgata [21]

Answer:

Step-by-step explanation:

Given

$6x_1-9x_2=8$

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The given system is $AX=B$ can be represented by

$\begin{bmatrix}6 &-9 \\ 9 & k\end{bmatrix}\begin{bmatrix}x_1\\ x_2\end{bmatrix}=\begin{bmatrix}8\\ -1\end{bmatrix}$

The given system is consistent when determinant of A is not equal to zero

$|A|$

$|A|=6k-(-81)=6k+81$

$k\neq \frac{-27}{2}$

i.e. system is consistent for all value of k except $k=\frac{-27}{2}$

$R-\frac{-27}{2}$

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3 years ago

Read 2 more answers