x-coordinates for the maximum points in any function f(x) by f'(x) =0 would be x = π/2 and x= 3π/2.
<h3>How to obtain the maximum value of a function?</h3>
To find the maximum of a continuous and twice differentiable function f(x), we can firstly differentiate it with respect to x and equating it to 0 will give us critical points.
we want to find x-coordinates for the maximum points in any function f(x) by f'(x) =0
Given f(x)= 4cos(2x -π)
In general 
from x = 0 to x = 2π :
when k =0 then x = π/2
when k =1 then x= π
when k =2 then x= 3π/2
when k =3 then x=2π
Thus, X-coordinates of maximum points are x = π/2 and x= 3π/2
Learn more about maximum of a function here:
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Answer:
15%
Step-by-step explanation:
Answer:
Par 1) 19.10 inches
Part 2) 39 days
Step-by-step explanation:
we know that
Asheville
47.71 in
124 days
Wichita
28.61 in
85 days
Part 1) About how many more inches of rain did Asheville get than Wichita?
In this part subtract the number of inches of rain in Wichita from the number of inches of rain in Asheville
so
Part 2) About how many more days did it rain in Asheville than Wichita?
n this part subtract the number of days of rain in Wichita from the number of days of rain in Asheville
so
Answer:
8(a+2)
Step-by-step explanation:
can i have the brainliest answer
I'm guessing you needed this factored and apologies for the lateness, this popped up after I answered another question.
12m³ - 22m² - 70m
2m(6m² - 11m - 35)
2m(6m² + 10m - 21m - 35)
2m(2m(3m + 5) - 7(3m + 5))
Your factored answer is:
2m(2m - 7)(3m + 5)
