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3. Sqrt of 40
4. Sqrt of 148
Distance formula is sqrt of (x-x1)^2+(y-y1)^2
So (-4-2)^2+ (3-5)^2
(-6)^2+(-2)^2
36+4
Sqrt of 40
Do the same process for 4!
Ps don’t forget to keep the square root
Answer:
thank you hahahahahahaha <3
Answer:
C. 0 ≤ X ≤ 40
Step-by-step explanation:
The equation is valid for positive values of x not greater than 40.
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Personally, I might put the domain at 1 ≤ x ≤ 40, because there's no point in using the equation (or parking the bus) if zero people are going on the trip.
