Answer and Step-by-step explanation:
Decreased by 20%
Answer:
0.281 ; 0.864
Step-by-step explanation:
1.)
p decreases as n increases (n increases, p--> 0)
λ ≥ 0
P(x = x) = (e^-λ * λ^x) ÷ x!
λ for Ford = 1.27
B) zero problems :
P(x = 0) :
(e^-1.27 * 1.27^0) ÷ 0! = 0.281
P(x = 0) = 0.281
Two or fewer problems :
P(x ≤ 2) = p(x = 0) + p(x = 1) + p(x = 2)
P(x ≤ 2) = 0.281 + 0.357 + 0.226
P(x ≤ 2) = 0.864
D.) It allows for early detection and thus adequate curtailment of the problem at an a stage in which it seems easier to curb.
A total of $27,000 was invested; part of it at 10% and part of it at 12%. The total yield was $2990. How much was invested at each rate?
Let
x -----> amount invested at 10%
(27,000-x) -----> amount invested at 12%
we have that
0.10(x)+0.12(27,000-x)=2990 ------> equation A
solve for x
0.10x+3,240-0.12x=2,990
0.12x-0.10x=3,240-2,990
0.02x=250
x=$12,500
so
27,000-x=27,000-12,500=$14,500
therefore
amount invested at 10% ----> $12,500
amount invested at 12% -----> $14,500
15% of 1085/6 =
15/100 * 1085 6/10 =
= 15/100 * 10856/10 =
= 3/100 * 10856/2 (after simplifying numerator of 15 and denominator of 10)
= 3/100 * 5428 =
= 16284/100 =
= <u>162,84</u>
Answer: 15% of 1085.6 is 162,84 (it's correct - I doublechecked it with calculator)
