Question

Select the correct answer from each drop-down menu.

Answer 1

Answer:

$we \: have \: ohms \: law \: h = {i}^{2} rt \\ \frac{h}{t} = {i}^{2} rt \div t = p \\ p = {i}^{2} r....(1) \\ we \: have \: v = ir \\ i = \frac{v}{r} .....(2) \\ put \: (2) \: in \: (1) \\ then \: p = { (\frac{v}{r}) }^{2} r \\ p = \frac{ {v}^{2} }{r} \\ v = \sqrt{pr} = {(pr)}^{ \frac{1}{2} } \\ 2) \\ here \: r = 32 \: and \: p = .5 \\ then \: v = \sqrt{32 \times .5} \\ = \sqrt{16} = 4volt \\ thank \: you$