The force in the rod when the temperature is 150 °F is 718.72 pounds-force.
<h3>How to determine the resulting the resulting force due to mechanical and thermal deformation</h3>
Let suppose that rod experiments a <em>quasi-static</em> deformation and that both springs have a <em>linear</em> behavior, that is, force (
), in pounds-force, is directly proportional to deformation. Then, the elongation of the rod due to <em>temperature</em> increase creates a <em>spring</em> deformation additional to that associated with <em>mechanical</em> contact.
Given simmetry considerations, we derive an expression for the <em>spring</em> force (), in pounds-force, as a sum of mechanical and thermal effects by principle of superposition:
(1)
Where:
- Spring constant, in pounds-force per inch.
- Spring deformation, in inches.
- Rod elongation, in inches.
The <em>rod</em> elongation is described by the following <em>thermal</em> dilatation formula:
(2)
Where:
- Coefficient of linear expansion, in 
.
- Initial length of the rod, in inches. 
- Initial temperature, in degrees Fahrenheit.
- Final temperature, in degrees Fahrenheit.
If we know 
, 
, 
, 
, 
and 
, then the force in the rod at final temperature is:
![F = \left(1000\,\frac{lb}{in} \right)\cdot \left[0.7\,in + 0.5\cdot\left(6.5\times 10^{-6}\,\frac{1}{^{\circ}F} \right)\cdot (48\,in)\cdot (150\,^{\circ}F-30\,^{\circ}F)\right]](https://tex.z-dn.net/?f=F%20%3D%20%5Cleft%281000%5C%2C%5Cfrac%7Blb%7D%7Bin%7D%20%5Cright%29%5Ccdot%20%5Cleft%5B0.7%5C%2Cin%20%2B%200.5%5Ccdot%5Cleft%286.5%5Ctimes%2010%5E%7B-6%7D%5C%2C%5Cfrac%7B1%7D%7B%5E%7B%5Ccirc%7DF%7D%20%5Cright%29%5Ccdot%20%2848%5C%2Cin%29%5Ccdot%20%28150%5C%2C%5E%7B%5Ccirc%7DF-30%5C%2C%5E%7B%5Ccirc%7DF%29%5Cright%5D)
The force in the rod when the temperature is 150 °F is 718.72 pounds-force. 
To learn more on deformations, we kindly invite to check this verified question: brainly.com/question/13774755
Answer:
The answer to your question is 23.2 ft
Step-by-step explanation:
Data
length square pyramid = 10 ft
width of a cube = 6 ft
height of the pyramid = ?
The surface area is equal in both figures.
Formula
Surface area of a cube = 6a²
Surface area of a square pyramid = ab + al = l x l + (l x h) /2
Process
1.- Calculate the surface area of the cube
Ac = 6(6)² = 6(36)
= 216 ft²
2.- Substitute data in the square pyramid formula
Ap = (10 x 10) + (10h)/2
3.- Equal both areas
216 = 100 + 5h
- Solve for h
216 - 100 = 5h
116 = 5h
h = 116 / 5
- Result
h = 23.2 ft
Answer:
I say that the answer is A, B, and C. I'm not positive but I think that is the answer.
Step-by-step explanation:
Tell me if I'm wrong it might just be B and C.
Answer:
136
Step-by-step explanation:
if two angles are supplementary then they have to add up 180. So if the measure of angle 2 is supplementary to the measure of angle 4 they have to add up to 180. you subtract 44 from 180 and you get 136. The measure of angle 4 is 136. 136 makes these two angles supplementary.
