The structure is in attachment.
Hexane is alkane (acyclic saturated hydrocarbon, carbon-carbon bonds<span> are </span>single) <span>of six </span>carbon atoms. Methoxy<span> group is the functional group consisting of a methyl group bound to oxygen. Iodo is substituent consists of ionide (element in 17 periodic group).</span>
Answer is: 4.02 grams of water are required.
Chemical reaction: BaH₂ + 2H₂O → Ba(OH)₂ + 2H₂.
Ideal gas law: p·V = n·R·T.
p = 755 mm Hg ÷ 760.0 mmHg / atm = 0.993 atm.
T = 25 + 273.15 = 298.15 K.
V(H₂) = 5.50 L.
R = 0,08206 L·atm/mol·K.
n(H₂) = 0.993 atm · 5.5 L ÷ 0,08206 L·atm/mol·K · 298.15 K.
n(H₂) = 0.223 mol.
From chemical reaction: n(H₂O) : n(H₂) = 1 : 1.
n(H₂O) = 0.223 mol.
m(H₂O) = 0.223 mol · 18 g/mol.
m(H₂O) = 4.02 g.
It's just a way to create an ovum with a donor nucleus. It is done by implanting a donor nucleus (from the somatic cell) into an egg cell, or "enucleated oocyte." <span />
2C6H14 + 19O2 ===> 12CO2 + 14H2O ... balanced equation
moled hexane present = 2.6 g x 1 mole/130 g = 0.02 moles
moles O2 present = 5.29 g x 1 mole/32 g = 0.165 moles
Which reactant is limiting? Hexane = 0.02/2 = 0.01; O2 = 0.165/19 = 0.0087
Thus O2 is limiting...
moles of H2O that can be produced =0.165 moles O2 x 14 H2O/19 CO2 = 0.122 moles H2O
Mass H2O = 0.122 moles x 18 gm/mole = 2.20 g (to 3 sig. figs.)
