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stepan [7]
3 years ago
15

Which ketone in each pair is more reactive?

Chemistry
1 answer:
KiRa [710]3 years ago
4 0

Answer:

a. 2-heptanone is more reactive than 4-heptanone

b. chloromethyl phenyl ketone is more reactive than bromomethyl phenyl ketone

Explanation:

The reactivity of the carbonyl compound (ketone ) is affected by the steric effect. The steric effect is a hindrance that occurs in the structure or reactivity of a molecule, which is affected by the physical size and the proximity of the adjacent parts of the molecule.

Between 2-heptanone or 4-heptanone, 2-heptanone is more reactive than 4-heptanone. This is because 2-heptanone is less affected by the steric hindrance, unlike the 4-heptanone.

Similarly, the reactivity of the carbonyl compound (ketone) is also affected by the polarity on the carbon compound, which is associated with how electronegative the substituent attached is to the carbonyl compound. From the periodic table, the electronegativity of the Halogen family decreases down the group. Therefore chlorine is more electronegative than bromine.

As such, chloromethyl phenyl ketone is more reactive than bromomethyl phenyl ketone.

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How can i find the number of electrons are gained or lost
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An atom contains 5 protons, 6 neutrons, and 6 electrons. What is the mass<br> number of this atom? *
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6 0
3 years ago
If 150 g dimethylhydrazine reacts with excess dinitrogen tetroxide and the product gases are collected at 127oC in an evacuated
zhuklara [117]

Answer : The the partial pressure of the nitrogen gas is 0.981 atm.

The total pressure in the tank is 2.94 atm.

Explanation :

The balanced chemical reaction will be:

(CH_3)_2N_2H_2(l)+2N_4O_4(l)\rightarrow 3N_2(g)+4H_2O(g)+2CO_2(g)

First we have to calculate the moles of dimethylhydrazine.

Mass of dimethylhydrazine = 150 g

Molar mass of dimethylhydrazine =60.104 g/mole

\text{Moles of dimethylhydrazine}=\frac{\text{Mass of dimethylhydrazine}}{\text{Molar mass of dimethylhydrazine}}

\text{Moles of dimethylhydrazine}=\frac{150g}{60.104g/mole}=2.49mole

Now we have to calculate the moles of N_2 gas.

From the balanced chemical reaction we conclude that,

As, 1 mole of (CH_3)_2N_2H_2 react to give 3 moles of N_2 gas

So, 2.49 mole of (CH_3)_2N_2H_2 react to give 2.49\times 3=7.47 moles of N_2 gas

Now we have to calculate the partial pressure of nitrogen gas.

Using ideal gas equation :

PV=nRT\\\\P_{N_2}=\frac{nRT}{V}

where,

P = Pressure of N_2 gas = ?

V = Volume of N_2 gas = 250 L

n = number of moles  N_2 gas = 7.47 mole

R = Gas constant = 0.0821L.atm/mol.K

T = Temperature of N_2 gas = 127^oC=273+127=400K

Putting values in above equation, we get:

P_{N_2}=\frac{(7.47mole)\times (0.0821L.atm/mol.K)\times 400K}{250L}=0.981atm

Thus, the partial pressure of the nitrogen gas is 0.981 atm.

Now we have to calculate the total pressure in the tank.

Formula used :

P_{N_2}=X_{N_2}\times P_T

P_T=\frac{1}{X_{N_2}}\times P_{N_2}

P_T=\frac{1}{(\frac{n_{N_2}}{n_T})}\times P_{N_2}

P_T=\frac{n_{T}}{n_{N_2}}\times P_{N_2}

where,

P_T = total pressure = ?

P_{N_2} = partial pressure of nitrogen gas = 0.981 atm

n_{N_2} = moles of nitrogen gas = 3 mole  (from the reaction)

n_{T} = total moles of gas = (3+4+2) = 9 mole  (from the reaction)

Now put all the given values in the above formula, we get:

P_T=\frac{9mole}{3mole}\times 0.981atm=2.94atm

Thus, the total pressure in the tank is 2.94 atm.

8 0
3 years ago
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