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Gelneren [198K]
3 years ago
15

Determine the number of ions produced in the dissociation of the compound listed. MgBr₂

Chemistry
1 answer:
Ne4ueva [31]3 years ago
3 0

Explanation:

A dissociation reaction is defined as a reaction in which a compound dissociates into its constituent particles.

For example, MgBr_{2} \rightarrow Mg^{2+} + 2Br^{-}

For a neutral compound, it is required that the charges must be balanced between the combining atoms.

Here, MgBr_{2} is the neutral compound as charge +2 on one atom of magnesium is balanced by 2 atoms of Br^{-} ion.

Therefore, we can conclude that in total the number of ions produced in the dissociation of MgBr_{2} compound is 3.

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Read 2 more answers
How many grams of NaF should be added to 500 mL of a 0.100 M solution of HF to make a buffer with a pH of 3.2
Korolek [52]

Answer:

2.25g of NaF are needed to prepare the buffer of pH = 3.2

Explanation:

The mixture of a weak acid (HF) with its conjugate base (NaF), produce a buffer. To find the pH of a buffer we must use H-H equation:

pH = pKa + log [A-] / [HA]

<em>Where pH is the pH of the buffer that you want = 3.2, pKa is the pKa of HF = 3.17, and [] could be taken as the moles of A-, the conjugate base (NaF) and the weak acid, HA, (HF). </em>

The moles of HF are:

500mL = 0.500L * (0.100mol/L) = 0.0500 moles HF

Replacing:

3.2 = 3.17 + log [A-] / [0.0500moles]

0.03 = log [A-] / [0.0500moles]

1.017152 = [A-] / [0.0500moles]

[A-] = 0.0500mol * 1.017152

[A-] = 0.0536 moles NaF

The mass could be obtained using the molar mass of NaF (41.99g/mol):

0.0536 moles NaF * (41.99g/mol) =

<h3>2.25g of NaF are needed to prepare the buffer of pH = 3.2</h3>
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2 years ago
PLEASE HELP!! How could using either more or less of a chemical in a scientific experiment cause a change in results?
charle [14.2K]
The chemical could have more or less of a reaction to the other chemicals in the experiment
4 0
3 years ago
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