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Andrei [34K]
3 years ago
8

Which of the following equations have the correct solution select all that apply

Mathematics
1 answer:
KATRIN_1 [288]3 years ago
7 0
The First One
The Third One
The Forth One

The others result in a lower number than what they are supposed to be. The 3 correct ones end with the exact number of the equations solution number.
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Multiplying a certain even number by 4 then subtracting 16 gives you the next consecutive even number. Find the original number
anyanavicka [17]

Let 2k represent the original even number (such that k is an integer)

then 2(k + 1) is the next consecutive even number.

4(2k) - 16 = 2(k + 1)

8k - 16 = 2k + 2

6k = 18

k = 3

since 2k represents the original number, then 2(3) = 6 is the oroginal number

Answer: 6

3 0
3 years ago
Can someone please please please help me please
anzhelika [568]

#9 is answer A) yes,

#10 the answer is A) (n,j)

5 0
3 years ago
A survey of 76 commercial airline flights of under 2 hours resulted in a sample average late time for a flight of 2.55 minutes.
nika2105 [10]

Answer:

The best point of estimate for the true mean is:

\hat \mu = \bar X = 2.55

2.55-1.96\frac{12}{\sqrt{76}}=-0.148    

2.55+1.96\frac{12}{\sqrt{76}}=5.248    

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

Step-by-step explanation:

Information given

\bar X=2.55 represent the sample mean for the late time for a flight

\mu population mean

\sigma=12 represent the population deviation

n=76 represent the sample size  

Confidence interval

The best point of estimate for the true mean is:

\hat \mu = \bar X = 2.55

The confidence interval for the true mean is given by:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

The Confidence level given is 0.95 or 95%, th significance would be \alpha=0.05 and \alpha/2 =0.025. If we look in the normal distribution a quantile that accumulates 0.025 of the area on each tail we got z_{\alpha/2}=1.96

Replacing we got:

2.55-1.96\frac{12}{\sqrt{76}}=-0.148    

2.55+1.96\frac{12}{\sqrt{76}}=5.248    

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

7 0
3 years ago
Find two positive numbers satisfying the given requirements.
Umnica [9.8K]

Answer:

8 and 19

Step-by-step explanation:

To some this, let's first list all the factors of 152. They are;

1, 2, 4, 8, 19, 38, 76, 152.

Now, let's arrange them to reflect being multiplied to get 152.

Thus;

1 × 152 = 152

2 × 76 = 152

4 × 38 = 152

8 × 19 = 152

Also, let's do the same for their sum;

1 + 152 = 153

2 + 76 = 78

4 + 38 = 42

8 + 19 = 27

Looking at the figures above, the ones that their product is 152 but have the least sum are 8 and 19

8 0
3 years ago
Kelly needs $125 to buy a dress for the dance. Her dad gave her five dollars for doing your chores and received $15 an hour to t
Debora [2.8K]
8 hours. 125 - 5 = 120. 120 / 15 = 8. Kelly will need to tutor for 8 hours minimum to buy the dress.
7 0
3 years ago
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