Answer: she has spent $60 dollars and she has 180 more to go
Step-by-step explanation:
Hello!
To solve this problem, we will use a system of equations. We will have one number be x and the other y. We will use substitutions to solve for each variable.
x+y=9
x=2y-9
To solve for the two numbers, we need to solve the top equation. The second equation shows that x=2y-9. In the first equation, we can replace 2y-9 for x and solve.
2y-9+y=9
3y-9=9
3y=18
y=6
We now know the value of y. Now we need to find x. We can plug in 6 for y in the second equation to find x.
x=2·6-9
x=12-9
x=3
Just to check, we will plug these two numbers into the first equation.
3+6=9
9=9
Our two numbers are three and six.
I hope this helps!
Answer:
Median = 7
upper quartile = 10
lower quartile is 6
Step-by-step explanation:
The median is the middle line in the box
Median = 7
The upper quartile is the right line of the box
upper quartile = 10
The lower quartile is the left line of the box
lower quartile is 6
6 inches
6 1/14 inches
Since area is defined as length multiplied by width, this is a simple matter of division. I suspect this problem is more a matter of handling fractions, so to make things easier, convert the fractions to improper fractions in order to do the math, then convert to proper fractions after you've gotten the result. Since the area of each rectangle is 12 3/4, multiply 12 by 4 and then add 3 to get 51/4 as the area. Doing the same for the values 2 1/8 and 2 1/10 gives sizes of 17/8 and 21/10 for the widths respectively. So
51/4 / 17/8 = 51/4 * 8/17 = 408/68 = 6/1 = 6
51/4 / 21/10 = 51/4 * 10/21 = 510/84 = 85/14 = 6 1/14
