M= 95-120 / 50-100 = -25 / -50 = 1/2
I used the formula m= y2 - y1 / x2 - x1
The minimum surface area that such a box can have is 380 square
<h3>How to determine the minimum surface area such a box can have?</h3>
Represent the base length with x and the bwith h.
So, the volume is
V = x^2h
This gives
x^2h = 500
Make h the subject
h = 500/x^2
The surface area is
S = 2(x^2 + 2xh)
Expand
S = 2x^2 + 4xh
Substitute h = 500/x^2
S = 2x^2 + 4x * 500/x^2
Evaluate
S = 2x^2 + 2000/x
Differentiate
S' = 4x - 2000/x^2
Set the equation to 0
4x - 2000/x^2 = 0
Multiply through by x^2
4x^3 - 2000 = 0
This gives
4x^3= 2000
Divide by 4
x^3 = 500
Take the cube root
x = 7.94
Substitute x = 7.94 in S = 2x^2 + 2000/x
S = 2 * 7.94^2 + 2000/7.94
Evaluate
S = 380
Hence, the minimum surface area that such a box can have is 380 square
Read more about surface area at
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1) 3+2+15=20
2) 3/4= 27/36 1/9=4/36
3) 27/36+4/36=31/36
4) 26/27=936/972 31/36= 637/972
5) 936/972 + 637/972= 1573/972= 1 601/972
Answer:
bro i think its 10
Step-by-step explanation:
