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2 years ago

1. 2x-(3y +4)=2x-3y +4 What’s wrong with it

Mathematics

2 answers:

Karo-lina-s [1.5K]2 years ago

8 0

Answer:

Nothing

Step-by-step explanation:

2x-(3y+4)=2x-3y+4

The parenthesis didnt change anything.

this is a infinite solution problem.

wolverine [178]2 years ago

5 0

Answer:

2x-(3y +4)=2x-3y+4

Nothing is wrong with it

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Can someone explain how to convert 70kg to lbs? i need to show work on my test.

Jlenok [28]

Answer:

70 kg is 154.3 lbs.

Step-by-step explanation:

There is 0.453592 kilograms per pound. That is just the conversion rate.

To find how many lbs 70 kg is, we do 70/0.453592 which is 154.3236.

3 0

3 years ago

Find the perimeter of the triangle defined by the coordinates (7, 1), (-6, 1), and (10, 6). (Round to nearest tenth)

matrenka [14]

Answer:

$35.6\ units$

Step-by-step explanation:

we know that

The perimeter of triangle is equal to the sum of the length of the three sides

Let

$A(7, 1), B(-6, 1), C(10, 6)$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Find the distance AB

$A(7, 1), B(-6, 1)$

substitute in the formula

$d=\sqrt{(1-1)^{2}+(-6-7)^{2}}$

$d=\sqrt{(0)^{2}+(-13)^{2}}$

$dAB=13\ units$

Find the distance BC

$B(-6, 1), C(10, 6)$

substitute in the formula

$d=\sqrt{(6-1)^{2}+(10+6)^{2}}$

$d=\sqrt{(5)^{2}+(16)^{2}}$

$dBC=16.8\ units$

Find the distance AC

$A(7, 1), C(10, 6)$

substitute in the formula

$d=\sqrt{(6-1)^{2}+(10-7)^{2}}$

$d=\sqrt{(5)^{2}+(3)^{2}}$

$dAC=5.8\ units$

Find the perimeter

$P=dAB+dBC+dAC$

$P=13+16.8+5.8=35.6\ units$

4 0

2 years ago

a 5-gallon mixture contains 40% acid. A 3-gallon mixture contains 50% acid. what percent acid is obtained by putting the two mix

natta225 [31]

so the 5 gallons ones is 40% acid, how much acid solute is in it anyway? well just 40% of 5 or namely 0.4*5 = 2 gallons.

the 3 gallons one is 50%, likewise it has 0.50 * 3 = 1.5 gallons of acid solute in it.

$\begin{array}{lcccl} &\stackrel{solution}{quantity}&\stackrel{\textit{\% of }}{amount}&\stackrel{\textit{gallons of }}{amount}\\ \cline{2-4}&\\ \textit{1st mixture}&5&0.4&\stackrel{(5)(0.4)}{2}\\ \textit{2nd mixture}&3&0.5&\stackrel{(3)(0.5)}{1.5}\\ \cline{2-4}&\\ mixed&8&p&3.5 \end{array} \\\\\\ 8p=3.5\implies p=\cfrac{3.5}{8}\implies p=0.4375\implies p=\stackrel{\%}{43.75}$