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mr Goodwill [35]
3 years ago
7

Can anybody explain how to do this? The answer I keep getting isn't one of the options.

Mathematics
1 answer:
Nastasia [14]3 years ago
3 0
I think is D


5^-2*25^-1
5^-2*5^-2
5^-4
1/5^4
1/625
0,0016, 5^-4
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Curve fitting is a methode of finding
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The method of least squares is a widely used method of fitting curve for a given data

Step-by-step explanation:

It is the most popular method used to determine the position of the trend line of a given time series. The trend line is technically called the best fit. ... The sum of the deviations of y from their corresponding trend values is zero.

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3 years ago
|-19+9|/3-|14-22|/9<br> give me an answer
MArishka [77]

Answer:22/

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= 2 4/

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≅ 2.4444444

Step-by-step explanation:

Add: -19 + 9 = -10

Absolute value: abs(the result of step No. 1) = abs(-10) = 10

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Subtract: 14 - 22 = -8

Absolute value: abs(the result of step No. 4) = abs(-8) = 8

Divide: the result of step No. 5 / 9 = 8 / 9 = 0.88888888888889 = 8/

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Subtract: the result of step No. 3 - the result of step No. 6 = 10/

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6 0
2 years ago
Select all of the following 2D shapes that may be formed by slicing a square pyramid?
ivann1987 [24]

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Step-by-step explanation:

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8 0
3 years ago
HELP PLEASE!!!!!
FromTheMoon [43]

Answer:

positve and linear realationship

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
the half-life of strontium-90 is approximately 29 years. how much of a 500 g sample of strontium-90 will remain after 58 years​
Yuliya22 [10]

Answer:  125 g

<u>Step-by-step explanation:</u>

A = P_o\cdot e^{kt}\\\\\text{First, use the given information to find k:}\\\\\bullet A=\dfrac{1}{2}P_o\\\\\bullet k = unknown\\\\\bullet t=29\text{ years}\\\\\dfrac{1}{2}P_o=P_o\cdot e^{k(29)}\\\\\\\dfrac{1}{2}=e^{k(29)}\qquad divided\ both\ sides\ by\ P_o\\\\\\ln\bigg(\dfrac{1}{2}\bigg)=ln\bigg(e^{k(29)}\bigg)\qquad applied\ ln\ to\ both\ sides\\\\\\ln\bigg(\dfrac{1}{2}\bigg)=29k\qquad simplified-ln\ and\ e\ cancel\ out\\\\\\\dfrac{ln\bigg(\dfrac{1}{2}\bigg)}{29}=k\qquad divided\ 29\ from\ both\ sides\\\\\\-0.0239=k

\text{Now, use the following in the equation to solve for A:}\\\\\bullet A=unknown\\\bullet P_o=500\\\bullet k=-0.0239\\\bullet t=58\text{ years}\\\\A=500\cdot e^{(-0.0239)(58)}\\\\.\quad=500\cdot e^{-1.386}\\\\.\quad=125

8 0
4 years ago
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