Answer: I'm not sure, but I think it would be a <em>total lunar eclipse </em>
Answer:
W = -0.480 J
Explanation:
given,
q₁ = 4 μC
q₂ = -4.10 μC
b = 0.381
k = 8.99 × 10⁹ Nm²/C²
![W = [-147.436\times (5.88-2.62)\times 10^{-3}]J](https://tex.z-dn.net/?f=W%20%3D%20%5B-147.436%5Ctimes%20%285.88-2.62%29%5Ctimes%2010%5E%7B-3%7D%5DJ)
W = -0.480 J
Work done by the electric force W = -0.480 J
The weight of 20 kg is
(mass) x (gravity) =
(20 x 9.8) = 196 newtons, downward.
There must be a force of 196 newtons upward on the mass.
Otherwise the mass is accelerating either up or down.
Answer:
angle is 19.85°
Explanation:
given data
grade = 36.1 %
vertically distance y = 36.1 m
horizontal distance x = 100 m
to find out
angle
solution
we know that according to question here
it make a triangle shape that contain 100 m base and height 36.1 m
and make angle with base is θ
so by triangle we know here
tanθ = y/x ..........1
so we now put x and y and find θ
tanθ = 36.1 / 100
tanθ = 0.361
θ = 19.85°
so angle is 19.85°
As per the given question,
Focal length of the concave mirror(f)=0.25m
position of virtual image form the mirror (v)=0.04m
let the position of the object from the concave mirror (u)=?
u=3.44cm
