SUUDVA

Physics

1 answer:

inn [45]3 years ago

5 0

3. The magnetic field is the area around a magnet in which there is magnetic force.

(1) Single touch method (2) Double touch method (3) Using electric current.

4. The difference between a permanent magnet and a temporary magnet is in their atomic structures. Permanent magnets have their atoms aligned all the time. Temporary magnets have their atoms aligned only while under the influence of a strong external magnetic field.

Electromagnets are temporary and artificial magnets. They are magnets that are only magnetic when there is a coil of wire with electricity running through it.

Motors and generators, Transformers, Relays, Electric bells and buzzers, Loudspeakers and headphones, Actuators such as valves, Magnetic recording and data storage equipment: tape recorders, VCRs, hard disks, MRI machines etc. (there is a lot)

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Assuming the density of the wine to be 1.0 g/ml, what caloric content does the alcohol (ethanol) in a 6-oz glass of wine (177 ml

viktelen [127]

mass = 177 x 1.0 g/mL= 177 g mass ethanol = 177 x 10.6/100 = 18.8 g moles = 18.8 g/46.069 g/mol = 0.408 1367 kJ/mol x 0.408 mol= 557.9 kJ

4 0

3 years ago

Read 2 more answers

A heat engine has a maximum possible efficiency of 0.780. If it operates between a deep lake with a constant temperature of-24.8

Volgvan

Answer : The temperature of the hot reservoir (in Kelvins) is 1128.18 K

Explanation :

Efficiency of carnot heat engine : It is the ratio of work done by the system to the system to the amount of heat transferred to the system at the higher temperature.

Formula used for efficiency of the heat engine.

$\eta =1-\frac{T_c}{T_h}$

where,

$\eta$ = efficiency = 0.780

$T_h$ = Temperature of hot reservoir = ?

$T_c$ = Temperature of cold reservoir = $-24.8^oC=273+(-24.8)=248.2K$

Now put all the given values in the above expression, we get:

$\eta =1-\frac{T_c}{T_h}$

$0.780=1-\frac{248.2K}{T_h}$

$T_h=1128.18K$

Therefore, the temperature of the hot reservoir (in Kelvins) is 1128.18 K

8 0

3 years ago

Engineers and science fiction writers have proposed designing space stations in the shape of a rotating wheel or ring, which wou

Gennadij [26K]

Answer:

a. The station is rotating at $1.496 \frac{rev}{min}$

b. the rotation needed is $2.8502 \frac{rev}{min}$

Explanation:

We know that the centripetal acceleration is

$a_{c}= \omega ^2 r$

where $\omega$ is the rotational speed and r is the radius. As the centripetal acceleration is feel like an centrifugal acceleration in the rotating frame of reference (be careful, as the rotating frame of reference is <u>NOT INERTIAL,</u> the centrifugal force is a fictitious force, the real force is the centripetal).