Answer:
Explanation:
We are given that
Diameter of wire=d=4.12 mm
Radius of wire=
Current=I=
Drift velocity=
We have to find the density of free electrons in the metal
We know that
Density of electron=
Using the formula
Density of free electrons=
By using Area of wire=
Density of free electrons=
Explanation:
use torque =I\alpha
and obtain alpha by \alpha =(17×2×3.14)/60×5
As velocities are tangent, the value of both Particle A and Particle B would be same for that point O (Intersecting point)
a = v / t
Here, v = 7, t = 6
So, a = 7/6
a = 1.17
As the graph is decreasing, value of acceleration would be negative.
So, a = -1.17 m/s²
In short, Your Answer would be Option C
Hope this helps!
Hey, how much is this a grade for?