Answer:
Explanation:
Given that,
Speed of transverse wave, v₁ = 20 m/s
Tension in the string, T₁ = 6 N
Let T₂ is the tension required for a wave speed of 30 m/s on the same string. The speed of a transverse wave in a string is given by :
........(1)
T is the tension in the string
is mass per unit length
It is clear from equation (1) that :
So, the tension of 13.5 N is required for a wave speed of 30 m/s. Hence, this is the required solution.
Answer:
period = 0.65 sec
Explanation:
from the question we are given the following
extension (x) = 2.6 cm = 0.026 m
mass of object (Mo) = 7 g = 0.007 kg
mass of block (Mb) = 28 g = 0.028 g
acceleration due to gravity (g) = 9.8 m/s^{2}
period = 2π x
where k is the spring constant of the spring
and k = \frac{Mo x g}{x}
k = \frac{0.007 x 9.8}{0.026}
k = 2.64 N/m
now period = 2π x
period = 0.65 sec
Answer:
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Answer:
0.098 N
Explanation:
From the question,
Spring scale reading = W-U............... Equation 1
Where W = weight of the cube, U = upthrust.
W = mg
Where m = mass of the cube, g = acceleration due to gravity.
Given: m = 11 g = 0.011 kg, g = 9.8 m/s².
W = 0.011(9.8)
W = 0.1078 N.
From Archimedes principle,
Upthrust = weight of water displaced.
U = (Density of water×volume of metal cube)×acceleration due to gravity.
U = (D×V)g
Given: D = 1000 kg/m², V = 1 cm³ = (1/1000000) = 1×10⁻⁶ m³, g - 9.8 m/s²
U = 1000(9.8)(10⁻⁶)
U = 0.0098 N.
Substitute the value of W and U into equation 1
Reading of the spring scale = 0.1078-0.0098
Reading of the spring scale = 0.098 N
Your kinetic energy goes down and your potential energy rises. This happens till you reach the top or start falling, in which the opposite happens. Hope this helps!