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brilliants [131]
3 years ago
6

Please Show Work and Be Done Soon!!

Mathematics
1 answer:
masya89 [10]3 years ago
8 0

The value of x from the diagram is 18degrees

An angle is a line where two or more lines meet.

The magnitude of two lines is known to be parallel if they have the same magnitude.

From the diagram shown, we can see that line BC is parallel to line ED

This shows that the following are true:

  • <C = <D
  • 8x and 2x are supplementary

If the two angles are supplementary, then:

8x + 2x  = 180

10x = 180

x = 180/10

x = 18 degrees

Hence the value of x is 18degrees

Learn more here: brainly.com/question/19023162

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What is a necessary step for constructing perpendicular lines through a point off the line?
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Draw arcs on either side of a given point on the line

To construct a line perpendicular to another line through a point on the line:

Measure a length from that point to one edge of the line

Draw two intersecting arcs on either sides of the line

Draw a straight line from the intersecting point of the arcs to the point on the existing line.

The new line drawn is a perpendicular line.

The only step necessary out of the given choices is "Draw arcs on either side of a given point on the line"

Option C is the correct choice

Learn more here: brainly.com/question/929137

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C is the answer to this question.
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42% of attendees at Martika's wedding order the steak for dinner. There are 350 people at the wedding. How many people will eat
Dominik [7]

Answer:

147 people

Step-by-step explanation:

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Differentiate. F(x) = (x3 - 3)2/3 2x f'(x) - 3 8 O f'(x) = 3 8 2x2 f'(x) 3 VX3 -8 f(x) 3 V3-8​
oee [108]

Answer:

f'(x) =   \frac{2{x}^{2}}{ \sqrt[3]{( {x}^{3}  - 8) } }

Step-by-step explanation:

f(x) = ( {x}^{3}  - 8)^{ \frac{2}{3} }  \\  \\ f'(x) =  \frac{2}{3} ( {x}^{3}  - 8)^{ \frac{2}{3} - 1 } (3 {x}^{2}  - 0) \\  \\ f'(x) =  \frac{2}{3} ( {x}^{3}  - 8)^{ \frac{2 - 3}{3}  }  \times 3 {x}^{2} \\  \\ f'(x) =  2{x}^{2}( {x}^{3}  - 8)^{ \frac{ - 1}{3}  } \\  \\ f'(x) =   \frac{2{x}^{2}}{( {x}^{3}  - 8)^{ \frac{ 1}{3}  } } \\  \\ \huge \red{ \boxed{ f'(x) =   \frac{2{x}^{2}}{ \sqrt[3]{( {x}^{3}  - 8) } } }}

3 0
3 years ago
3(x -y) + 4 if X = 3 and y = 2
Alchen [17]

Answer:

7

Step-by-step explanation:

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3(1)+4

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7

7 0
3 years ago
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