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liq [111]
2 years ago
11

Given that cos(x)=−0.65, what is cos(−x)

Mathematics
1 answer:
Tanzania [10]2 years ago
7 0

Step-by-step explanation:

Cos(-x) = cos(x)

Therefore, cos(-x)= -0.65

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Given: Q = 7m + 3n, R = 11 - 2m, S = n + 5, and T = -m - 3n + 8. Simplify R - S + T
galben [10]

Q=7m+3n\\R=11-2m\\S=n+5\\T=-m-3n+8\\\\R-S+T=(11-2m)-(n+5)+(-m-3n+8)\\\\=11-2m-n-5-m-3n+8\\\\=(-2m-m)+(-n-3n)+(11-5+8)\\\\=\boxed{-3m-4n+14}

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3 years ago
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3 years ago
Cos(0.5)+cos(0.5+2(3.14159265))+cos(0.5+4(3.14159265))
aleksandr82 [10.1K]

Answer:

2.63274768567

Step-by-step explanation:

First, note that 3.1415... is p, so 2(3.1415...) is 2pi and 4(3.1415...) is 4pi.

2pi and 4pi are full rotations, which will lead to the same cosine (i.e. cos(x) = cos (x+2pi) = cos(x+4pi) = ... = cos (x+2k*pi)).

So, the expression equals cos0.5 + cos 0.5 + cos0.5 = 3cos0.5 = 3(0.87758256189) = 2.63274768567

I hope this helps! :)

7 0
3 years ago
Can someone make sure the first 3 questions are correct and help me on the 4th one?
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Sorry, I'm no help because I have no idea how to do those!
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