Question

Someone just robbed a bank. The police set a triangular perimeter of 16 kilometers where the robber may be hiding. Two of the three
coordinates for this triangular perimeter are (2, 2) and (2, -1). Each unit represents a kilometer. The area covered is a 12 square kilometers
Which of the following is the third coordinate of the triangular perimeter?

Answer 1

Answer:

Step-by-step explanation:

Perimeter = 16 km

s = 8 km

Area = $\sqrt{s(s-a)(s-b)(s-c)}$

Area = 12 sq km

Let the third coordinate be (x,y).

Then, a = $\sqrt{(2-2)^{2}+(2-(-1))^{2} }$

=3

b =  $\sqrt{(x-2)^{2}+(y-2)^{2} }$

c =  $\sqrt{(x-2)^{2}+(y-(-1))^{2} }$

Solving, a+b+c = 16

and using area equation we get

x = -6

y = 2