Question

Find the square Root of \sqrt{37} " align="absmiddle" class="latex-formula">
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Answer 1

Answer:

$\approx \frac{73}{12}\left(1 - \frac{1} {2\cdot73^2}\right)$

Step-by-step explanation:

$= \sqrt{\frac{73^2-1) 1}{12^2}}$

$= \sqrt{\frac{73^2}{12^2}\cdot\frac{73^2-1}{73^2}}$

$= \sqrt{\frac{73^2}{12^2}}\sqrt{\frac{73^2-1}{73^2}}$

=$\frac{73}{12}\sqrt{1 - \frac{1}{73^2}}$

$\approx \frac{73}{12}\left(1 - \frac{1} {2\cdot73^2}\right)$