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andreev551 [17]
3 years ago
5

2. Assume that the reference variable r refers to a serializable object. Write code that serializes the object to the file Objec

tData.dat. in java
Computers and Technology
1 answer:
Dafna11 [192]3 years ago
3 0

Answer:

Carmen Katrit rgrtun fjdidnf cucixizshdbdbdjsisjsdndbdhdhduehebbwwwhwususiussjhsdbd

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Generate an array x that has n=100 random numbers that are uniformly distributed over the interval [0,1) . Look up how to use th
gladu [14]

Answer: np​.​random​.​uniform​(​0,​1,​100)

Explanation:

import numpy as np

#pass the random uniform generated array into x

x = np.random.uniform(low, high, size)

#here low = 0, high = 1, size = 100

x = no.random.uniform(0,1,100)

8 0
3 years ago
what are some steps Hector could have taken to ensure that his photographs were not ruined near the end of the shoot?
galben [10]

Answer:

make several extra copies of the pictures and frame them right away if they're printed out.

Explanation:

3 0
2 years ago
Difference between multidimensional arrays and an example​
weqwewe [10]

Answer:

The generic data structure of a n-dimensional array is a tensor.

An example with 3 dimension can be a cube that contains the following dimensions: users, items, time. That cube can represent the interactions of  users with verifiied pages of public interests (influencers or company/media pages) in time slots (e.g. weekly timeslots).

Explanation:

You can represent in a sparse 3-dimensional array (tensor) the combinations of which user interacted with wich item in a given timeslow.

5 0
3 years ago
The danger in using soy solvents is that they: A) Are not approved by the FDA B) Take paint off of surfaces where used C) Are no
tatuchka [14]

Take paint off surfaces

sp2

8 0
3 years ago
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You have a network with a subnet of 172.16.17.0/22. Which of the following is a valid host address?A. 172.16.17.1 255.255.255.25
Licemer1 [7]

Answer:

E. 172.16.18.255 255.255.252.0

Explanation:

Oh goodie, this is my home turf.

The answer is E) 172.16.18.255 255.255.252.0

This is because your subnet network ID includes mask \22, which means the ending with 255 255.255.252.0, which is standard for Class B. Only option E falls as an adequate host due to the network being 172.16.16 and broadcasting 16.19.

7 0
3 years ago
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