We know that
<span>sec a = 5/4
</span>sec(a)=1/cos(a)
then
cos (a)=1/sec(a)
cos (a)=1/(5/4)=4/5---> is positive because the function cos is positive in IV quadrant
the answer is cos(a)=4/5
⓵
-4ỿ = 8
Simplify the left side in order to isolate the ỿ!
-4ỿ = 8
+4 +4
Ỿ = 12
⓶
× + 3y - 3z = -26
Simplify the left side in order to isolate the ×, ỿ and z!
× + 3y - 3z = -26
÷3 ÷3
× + ỿ - 3z = -8,66 periodic
÷-3 ÷-3
× + ỿ + z = 2,88 periodic
⓷
2× - 5ỿ + z = 19
Simplify the left side in order to isolate the ×, ỿ and z!
2× - 5ỿ + z = 19
÷2 ÷2
× - 5ỿ + z = 9,5
÷-5 ÷-5
× + ỿ + z = -1,9
Answer:
c
Step-by-step explanation:
Differentiate both sides with respect to
:
When
, you have
For part (b), we now assume that
and
are functions of an independent variable, which we'll call
(for time). Now differentiating both sides with respect to
, we have
where the chain rule is used on the right side. We're told that
is decreasing at a constant rate of 0.1 units/second, which translates to
. So when
, you have
where the unit is again units/second.
Answer:
looks like 2
Step-by-step explanation:
Points where two lines cross are solutions they share
