Question

A chemical reaction was used to produce 2.95 moles of copper(II) bicarbonate, Cu(HCO3)2.

Answer 1

Answer:

About 547 grams.

Explanation:

We want to determine the mass of copper (II) bicarbonate produced when a reaction produces 2.95 moles of copper (II) bicarbonate.

To do so, we can use the initial value and convert it to grams using the molar mass.

Find the molar mass of copper (II) bicarbonate by summing the molar mass of each individual atom:

$\displaystyle \begin{aligned} \text{MM}_\text{Cu(HCO _3 ) _2 } &= (63.55 + 2(1.01)+2(12.01)+6(16.00))\text{ g/mol} \\ \\ &=185.59\text{ g/mol} \end{aligned}$

Dimensional Analysis:

$\displaystyle 2.95\text{ mol Cu(HCO _3 ) _2 }\cdot \frac{185.59 \text{ g Cu(HCO _3 ) _2 }}{1 \text{ mol Cu(HCO _3 ) _2 }} \Rightarrow 547 \text{ g Cu(HCO _3 ) _2 }$

In conclusion, about 547 grams of copper (II) bicarbonate is produced.