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natulia [17]
3 years ago
7

Describe one technology used to travel to space and one technology used to return from space

Chemistry
1 answer:
marysya [2.9K]3 years ago
8 0
<span>technology includes spacecraft, satellites, space stations, and support infrastructure, equipment, etc..</span>
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g When copper(II) chloride and sodium carbonate solutions are combined, solid copper(II) carbonate precipitates, leaving a solut
Elden [556K]

Answer:

When copper(II) chloride and sodium carbonate solutions are combined, solid copper(II) carbonate precipitates, leaving a solution of sodium chloride. Write the conventional equation, total ionic equation, and net ionic equation for this reaction.

Explanation:

The word equation for the reaction is:

Copper (II) chloride(aq) + sodium carbonate (aq) ->sodium chloride (aq) +           copper carbonate(s)

The balanced chemical equation of the reaction is:

CuCl_2(aq)+Na_2CO_3(aq)->2NaCl(aq)+CuCO_3(s)

The complete ionic equation is:

Cu^2+(aq)+2Cl^-(aq)+2Na^+(aq)+CO_3^2^-(aq)->2Cl^-(aq)+2Na^+(aq)+CuCO_3(s)\\

The net ionic equation is obtained from the complete ionic equation after removing the spectator ions:

Cu^2^+(aq)+CO_3^2^-(aq)->CuCO_3(s)

5 0
3 years ago
A hydrogen halide diffuses 1.49 times faster than HBr. This hydrogen halide is
marysya [2.9K]

To solve this problem, we must assume ideal gas behaviour so that we can use Graham’s law:

vA / vB = sqrt (MW_B / MW_A)

where,

<span>vA = speed of diffusion of A  (HBR)</span>

vB = speed of diffusion of B (unknown)

MW_B = molecular weight of B (unkown)

MW_A = molar weight of HBr = 80.91 amu

 

We know from the given that:

vA / vB = 1 / 1.49

 

So,

1/1.49 = sqrt (MW_B / 80.91)

MW_B = 36.44 g/mol

 

Since this unknown is also hydrogen halide, therefore this must be in the form of HX.

HX = 36.44 g/mol , therefore:

x = 35.44 g/mol

 

From the Periodic Table, Chlorine (Cl) has a molar mass of 35.44 g/mol. Therefore the hydrogen halide is:

HCl

6 0
3 years ago
The melting point of the metal potassium is 63.5c, while that of titanium is 1660c. what explanation can be given for this great
kiruha [24]

The melting point of potassium = 63.5^{0}C

Melting point of titanium = 1660^{0}C

Titanium has a stronger metallic bonding compared to potassium. Titanium being a transition metal has greater number of valence electrons (4 valence electrons) contributing to the valence electron sea compared to potassium which has only one valence electron. The atomic size of Titanium much lower than that of potassium, so the bonding between Titanium atoms is stronger than that of potassium. Hence, the melting point of Titanium is much higher than that of potassium.

3 0
3 years ago
Help Me plz I'm so tired
zvonat [6]
The answer is D :) have a nice day!
3 0
3 years ago
Read 2 more answers
What heavier element is created when hydrogen atoms fuse together in the sun’s core?
sergey [27]

Answer:

Helium is created from hydrogen in the sun's core.

Four hydrogen-1 nuclei fuse to produce

  • one helium-4 nucleus, two neutrons,
  • two positrons, and
  • two electron neutrinos.

Explanation:

Step One:

{\rm ^1_1 H + ^1_1 H\to ^2_1 H + e^{+}} + v_e.

Two hydrogen-1 nuclei fuse. One proton will convert to a neutron. The products will be

  • one hydrogen-2 nucleus,
  • one positron, and
  • one electron neutrino.

Step Two:

\rm ^1_1 H +^2_1 H \to ^3_2 He.

There are plenty of hydrogen-1 nuclei available in the core of the sun. The hydrogen-2 nucleus from step one will fuse with a hydrogen-1 nucleus. The product is

  • one helium-3 nucleus.

Step Three

\rm ^3_2 He + ^3_2 He \to ^4_2 He + ^1_1 H + ^1_1 H.

Two helium-3 nuclei from step two react with each other. The products are:

  • one helium-4 nucleus, and
  • two hydrogen-1 nuclei.

The overall reaction will be:

{\rm 6\; ^1_1 H \to ^4_2 He + 2\; ^1_1 H+2\; e^{+}}+v_\text{e}.

{\rm 4\; ^1_1 H \to ^4_2 He + 2\; e^{+}} + v_\text{e}

In other words, hydrogen nuclei in the core of the sun fuse together to form helium.

6 0
3 years ago
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