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shepuryov [24]
3 years ago
5

Which photographs show an object in orbit? Explain your answer.

Chemistry
2 answers:
daser333 [38]3 years ago
5 0

Answer:

the 3rd image

Explanation:

it is the 3rd image bcuz the third image shows an object or a body moving around a particular body of object

baherus [9]3 years ago
3 0
Last picture, because that ring explains something orbiting it.
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Always carry the microscope with________________-one on the ____________ and one underneath the____________ of the microscope
Ronch [10]

Answer:

Always carry the microscope with two hands. One on the arm and one underneath the base of the microscope.

5 0
3 years ago
What is the difference between speed and acceleration?<br> Please help :)
ioda

Answer:

Speed is how fast you are going at the moment but acceleration is how fast you are building up speed to get to a set point

Explanation:

4 0
3 years ago
Specify which atoms, if any, bear a formal charge in the Lewis structure given and the net charge for the species.
ozzi

Answer :

Formal charge on C:  (-1)

Formal charge on N:  (0)

Net charge: (-1)

Explanation :

First we have to determine the Lewis-dot structure of CN^-.

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

The given molecule is, CN^-

As we know that carbon has '4' valence electrons and nitrogen has '5' valence electrons.

Therefore, the total number of valence electrons in CN^- = 4 + 5 + 1= 10

According to Lewis-dot structure, there are 6 number of bonding electrons and 4 number of non-bonding electrons.

Now we have to determine the formal charge for each atom.

Formula for formal charge :

\text{Formal charge}=\text{Valence electrons}-\text{Non-bonding electrons}-\frac{\text{Bonding electrons}}{2}

\text{Formal charge on C}=4-2-\frac{6}{2}=-1

\text{Formal charge on N}=5-2-\frac{6}{2}=0

Net charge = -1 + 0 = -1

4 0
4 years ago
Which of the following naturally orccuing radioisotopes would be most useful in dating objects
Sergeu [11.5K]
Potassium -40half life = 1.28 ×10∧9.
Radioisotope can be used to determine the age of fossils, to treat skin disease, to sterilize foodstuffs, and also to sterilize surgical instruments.
Radioisotope dating is a way to estimate a fossil's age by a method of analyzing the elemental isotopes which are within the rocks which it is in.
3 0
3 years ago
The protein catalase catalyzes the reaction The Malcolm Baldrige National Quality Award aims to:
Marina CMI [18]

The question is missing a part, so the complete question is as follows:

The protein catalase catalyzes the reaction The Malcolm Bladrigde National Quality Awards aims to: 2H2O2 (aq) ⟶ 2H2O (l) + O2 (g) and has a Michaelis-Menten constant of KM = 25mM and a turnover number of 4.0 × 10 7 s -1. The total enzyme concentration is 0.012 μM and the intial substrate concentration is 5.14 μM. Catalase has a single active site. Calculate the value of Rmax (often written as Vmax) for this enzyme. Calculate the initial rate, R (often written as V0), of this reaction.

1) Calculate Rmax

The turnover number (Kcat) is a ratio of how many molecules of substrate can be converted into product per catalytic site of a given concentration of enzyme per unit of time:

Kcat = \frac{Vmax}{Et},

where:

Vmax is maximum rate of reaction when all the enzyme sites are saturated with substrate

Et is total enzyme concentration or concentration of total enzyme catalytic sites.

Calculating:

Kcat = \frac{Vmax}{Et}

Vmax = Kcat · Et

Vmax = 4×10^{7} · 1.2 × 10^{-8}

Vmax = 4.8 × 10^{-1} M

2) Calculate the initial rate of this reaction (R):

The Michaelis-Menten equation studies the dynamics of an enzymatic reaction. This model can explain how an enzyme enhances the rate of a reaction and how the reaction rate depends on the concentration of the enzyme and its substrate. The equation is:

V0 = \frac{[S].(Vmax)}{KM + [S]}, where:

[S] is the substrate's concentration

KM is the Michaelis-Menten constant

Substituting [S] = 5.14 × 10^{-6}, KM = 2.5 × 10^{-4} and Vmax = 4.8 × 10^{-1}, the result is V0 = 0.478 M.

The answers are Vmax = 4.8 × 10^{-1} M and V0 = 0.478 M.

 

7 0
4 years ago
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