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sasho [114]
2 years ago
6

5. On the Venn diagrams, shade the sets

Mathematics
1 answer:
lawyer [7]2 years ago
5 0
There can be like a where a b and c
You might be interested in
Draw a model to show the value of this expression.5 divided by 100
fomenos
Just draw a fraction to represent the fraction
3 0
3 years ago
Marcus spent 10 hours doing his homework last week. This week he spent 11 hours doing homework. He says that he spent 110% more
swat32

Answer:

Yes he is correct, If it was 100% then it would stay the same 10 hours. But since it's 110%, it is in fact 11.

Step-by-step explanation:

7 0
3 years ago
How many 6-digit numbers can be formed using the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, if repetitions of digits are allowed?
sveta [45]
There are 6 digits.  Each digit can take ten different numbers except for the first digit since it cannot be zero.

So:

9 x 10 x 10 x 10 x 10 x 10

900000 numbers.

Another way of thinking about this is to just count up to 999,999.  Obviously there are 999,999 different numbers here.  But since our number has to have 6 digits in them, we have to delete 99,999 numbers.  Thus there are 900,000 different numbers.
6 0
3 years ago
Given the following information, determine which lines are parallel and what justifies them being parallel.
weeeeeb [17]

Answers:

Blank 1 = p and r

Blank 2 = corresponding angles converse

==========================================================

Explanation:

Refer to the diagram below. I've marked lines p and r in red, and the angles 3 and 22 in blue. They are corresponding angles because they are both in the same southeast corner of their four-corner configuration.

If the corresponding angles are congruent, then the lines p and r are parallel by the aptly named corresponding angles converse

4 0
2 years ago
Final exam scores are normally distributed with a mean of 74 and a standard deviation of 6. Approximately, what percentage of fi
notka56 [123]

Answer:

81.86%

Step-by-step explanation:

We have been given that final exam scores are normally distributed with a mean of 74 and a standard deviation of 6.

First of all we will find z-score using z-score formula.

z=\frac{x-\mu}{\sigma}

z=\frac{68-74}{6}

z=\frac{-6}{6}=-1

Now let us find z-score for 86.

z=\frac{86-74}{6}    

z=\frac{12}{6}=2        

Now we will find P(-1<Z) which is probability that a random score would be greater than 68. We will find P(2>Z) which is probability that a random score would be less than 86.

Using normal distribution table we will get,    

P(-1

P(2>Z)=.97725  

We will use formula P(a to find the probability to find that a normal variable lies between two values.

Upon substituting our given values in above formula we will get,

P(-1

P(-1

Upon converting 0.81859 to percentage we will get

0.81859*100=81.859\approx 81.86

Therefore, 81.86% of final exam score will be between 68 and 86.  


3 0
3 years ago
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