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3 years ago

10

the price of stock decrease $2 per day for 4 days consecutive days what was the total change in the value of the stock over the

four-day period

2 answers:

ikadub [295]3 years ago

7 0

Each day it decrease $2. So just multiply $2 x 4 days. It changed a total of $8.

Aleks04 [339]3 years ago

7 0

It changed by a total of 8 dollars

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V5. Suppose you invest $5,000 at 9% interest, compounded annually, for 10 years. Determine the future value of your investment,

Elanso [62]

Answer: $11836.8

Step-by-step explanation:

Given. That :

Amount invested = $5000

Interest rate = 9% = 0.09

Period = 10 years, compounded annually

Using the compound interest formula :

A = p(1 + r/n)^nt

A = final amount

P = principal or invested amount

r = rate of interest

n = number of times interest Is applied per period

t = period

A = 5000(1 + 0.09/1)^(1*10)

A = 5000(1.09)^10

A = 5000 * 2.36736367459211723401

A = 11836.81837296058617005

= $11836.8

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3 years ago

Write a polynomial function of least degree with integral coefficients that has the

frutty [35]

A polynomial function of least degree with integral coefficients that has the

given zeros $f(x)=x^4+x^3+9x^2+9x$

Given

Given zeros are 3i, -1 and 0

complex zeros occurs in pairs. 3i is one of the zero

-3i is the other zero

So zeros are 3i, -3i, 0 and -1

Now we write the zeros in factor form

If 'a' is a zero then (x-a) is a factor

the factor form of given zeros

$\:\left(x-3i\right)\left(x-\left(-3i\right)\right)\left(x-0\right)\left(x-\left(-1\right)\right)\\\left(x-3i\right)\left(x+3i\right)\left(x-0\right)\left(x+1\right)$

Now we multiply it to get the polynomial

$x\left(x-3i\right)\left(x+3i\right)\left(x+1\right)\\x\left(x^2+9\right)\left(x+1\right)\\x\left(x^3+x^2+9x+9\right)\\x^4+x^3+9x^2+9x$

polynomial function of least degree with integral coefficients that has the

given zeros $f(x)=x^4+x^3+9x^2+9x$

Learn more : brainly.com/question/7619478

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3 years ago

A postage stamp has a area 1160mm^2. About how long is each side ?

Savatey [412]

Each side is about 290mm long

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3 years ago

h(x)= \dfrac{1}{8} x^3 - x^2h(x)= 8 1 x 3 −x 2 h, left parenthesis, x, right parenthesis, equals, start fraction, 1, divided b

Nesterboy [21]

Answer:

$\dfrac{1}{2}$

Step-by-step explanation:

Given the function $h(x)=\dfrac{1}{8}x^3-x^2$

The average rate of change of the function h(x) over the interval $a\le x\le b$ can be calculated using formula

$\dfrac{h(b)-h(a)}{b-a}$

In your case,

$a=-2,\\ \\b=2,$

so the average rate of change is

$\dfrac{h(2)-h(-2)}{2-(-2)}\\ \\=\dfrac{(\frac{1}{8}\cdot 2^3-2^2)-(\frac{1}{8}\cdot (-2)^3-(-2)^2)}{4}\\ \\=\dfrac{(1-4)-(-1-4)}{4}\\ \\=\dfrac{-3+5}{4}\\ \\=\dfrac{2}{4}\\ \\=\dfrac{1}{2}$

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solmaris [256]

Answer:

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2 years ago