For f(x)=1/x^2-3
Find
A) f(3)
B) f(2-h)
If f(x)=1/x^2-3, then f(3) = 1 / 3^2 - 3. The exponentiation here must be carried out first: f(3) = 1/9 - 3. Then f(3) = 1/9 - 27/9 = -26/9
If f(x)=1/x^2-3, then f(2-h) = 1 / [2-h]^2 - 3. This result may be left as is or expanded. In expanded form, we have:
1
f(2-h) = ------------------ - 3
4-4h +h^2
Answer:
24
Step-by-step explanation:
what is the smallest number which is a multiple of both 8 and 12? so, an multiple of 8 must have 2 as a factor at least 3 times. Similarly, multiples of 12 have at least two 2's and one 3. so we need 2x2x2x3 or 24 if every factor is to be included.
I'm not the best at explaining but you can search google to get the better Idea.
(btw this is for the fist question)
Y>0 because raising a number to a negative power doesn't make it negative
Answer:
17
Step-by-step explanation:
2x - 7 = 27
2x = 34
x = 17
Answer: Option 2
Step-by-step explanation:
